Answer:
Width = 16(√5) - 1
Step-by-step explanation:
We are told that the golden rectangle is 32 cm long.
Thus, length = 32 cm
We are also told that the ratio of the length to the width is; (1 + √5):2
Thus;
If a length of (1 + √5) yields a width of 2
Then, a length of 32 cm would yield a width of; (32 x 2)/(1 + √5)
So corresponding width = 64/(1 + √5)
We want to reduce this width to it's simplest radical form which means the denominator should have no square root.
Thus, let's multiply top and bottom by (1 - √5);
Width = 64 x (1 - √5)/[(1 + √5) x (1 - √5)]
Width = 64(1 - √5)/(1 - 5)
Width = 64(1 - √5)/(-4)
Width = -16(1 - √5)
Width = 16(√5 - 1)
Width = 16√5 - 1
Answer:
2
Step-by-step explanation:
3 1/5 * 5/8
First, change 3 1/5 into an improper fraction.
3 1/5 = 16/5
Then, substitute it into the original equation.
16/5 * 5/8
Multiply the numerators and denominators.
16*5 / 5*8 = 80 / 40 = 2
Answer:
The percentage increase in Jayana's postcard collection is 15%
Step-by-step explanation:
Jayana had 20 postcards last year
With 3 more postcards this year
From the given equation Quantity = Percent x Whole
Here;
Let P = Percent/100%
Quantity = Increment in postcard = 3 postcards
Whole = The total postcards from last year = 20 postcards
Hence,
3 postcards = P x 20 postcards
P = 3/20 = 0.15
Recall P = Percent/100%
∴ Percent = P x 100% = 0.15 x 100% = 15%
The percentage increase in Jayana's postcard collection is 15%
The ones in the bracket are a similar way of vectors.
hope that kinndaaa helps sorry xoxo
X=number of boys.
y=number of girls.
we suggest this system of equation
x/y=9/7
x=y+116
We solve this system of equation by substitution method.
(y+116)/y=9/7
7(y+116)=9y
7y+812=9y
9y-7y=812
2y=812
y=812/2=406
x=y+116
x=406+116=522
answer: At the school there are 522 boys and 406 girls.
to chek.
522/406=1.2857...
9/7=1.2857...
The number of boys (522) is equal to 406+116=522.