Find the area and perimeter of the polygons formed by the algebra tiles below: area: y X perimeter: 1 area: perimeter: 2
1 answer:
Answer:
The answer is below
Step-by-step explanation:
a)
The area of the figure = sum of the area of the individual polygons
The area of the figure = x + 1 + y + 1 + x = 2x + y + 2
The perimeter of the figure = sum of the length of the sides = 2(1 + (x + 1 + y + 1 + x)) = 2(2x + y + 3) = 4x + 2y + 6
b)
a)
The area of the figure = sum of the area of the individual polygons
The area of the figure = y² + xy + 1 + 1 + 1 = y² + xy + 3
The perimeter of the figure = sum of the length of the sides = (y + 1) + x + y + (y + 1) + y + 1 + 1 + 1 + x + 1 = 4y + 2x + 6
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Answer:
Step-by-step explanation:its ratxrat
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This is the symmetric property, for you divide 9 to both sides to get x, instead of adding (addition property of equality)
So symmetric property should be your answer
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