The answer is 600 because 1 out 3 is 60 so to find the bag multiply by two while to find 1 out 5 of her monet take 60 times 3 which is 180. 180 times 4 is the money she spent on her mobile phone so take the money spent on her mobile phone(720)minus the amount of money spent on the bag(120)
1. area of a pentagon when 1 side is x is
![\frac{x^2}{4}\sqrt{5(5+2\sqrt{5})}](https://tex.z-dn.net/?f=%5Cfrac%7Bx%5E2%7D%7B4%7D%5Csqrt%7B5%285%2B2%5Csqrt%7B5%7D%29%7D)
so if perimiter is 100 then one side is 100/5 or 20
area will be
![\frac{20^2}{4}\sqrt{5(5+2\sqrt{5})}](https://tex.z-dn.net/?f=%5Cfrac%7B20%5E2%7D%7B4%7D%5Csqrt%7B5%285%2B2%5Csqrt%7B5%7D%29%7D)
≈<span>688.2 square yards
2. area of a hexagon when 1 side is length x is
![\frac{3x^2\sqrt{3}}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B3x%5E2%5Csqrt%7B3%7D%7D%7B2%7D)
so if permiter is 100 then length of one side is 100/6 or about 16.666666666666
the area will be
![\frac{3(16.6666666)^2\sqrt{3}}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B3%2816.6666666%29%5E2%5Csqrt%7B3%7D%7D%7B2%7D)
≈721.7 square yards
3. area of a regular octagon with side lenghts x is
![2(1+\sqrt{2})x^2](https://tex.z-dn.net/?f=2%281%2B%5Csqrt%7B2%7D%29x%5E2)
so if 8 sides then side length of each is 100/8 or 12.5
area will be
![2(1+\sqrt{2})12.5^2](https://tex.z-dn.net/?f=2%281%2B%5Csqrt%7B2%7D%2912.5%5E2)
≈754.4 square yards
octagon wil have most space
you can tell because the more sides it has, the more it gets to a circle and the more area it encloses with a given perimiter
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Answer:
C. x + 9 = 11
Step-by-step explanation:
We are trying to identify which of the equations does not match with the others. In this case, solve for x in each equation:
Option A):
6 + x = 9
Subtract 6 from both sides:
6 (-6) + x = 9 (-6)
x = 9 - 6
x = 3
Option B):
15 = x + 12
Subtract 12 from both sides:
15 (-12) = x + 12 (-12)
15 - 12 = x
x = 3
Option C):
x + 9 = 11
Subtract 9 from both sides:
x + 9 (-9) = 11 (-9)
x = 11 - 9
x = 2
Option D):
7 + x = 10
Subtract 7 from both sides:
x + 7 (-7) = 10 (-7)
x = 10 - 7
x = 3
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As you can tell, all the equations end with x = 3 as there answers except C. x+9=11, making (C) your answer.
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If the distance between the fulcrum and the effort is increased, the distance that the effort must move the lever increases as well. Conversely, if the distance between the fulcrum and the load is decreased, the distance that the lever must move also decreases.
so we have too apply more force to pull the lever cause the distance is 1x smaller then mia lever so on mia lever we ull moree to get it to move!