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dimaraw [331]
3 years ago
15

PLESE HELP I WILL MARK BRAINEST PLEASE

Mathematics
1 answer:
FrozenT [24]3 years ago
7 0

Answer:

a) 23.0769% increase

b) 9.375% decrease

Step-by-step explanation:

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Find the missing side length. Round your answer to the nearest tenth.
EastWind [94]

Answer:

5.545

Step-by-step explanation:

This problem can be easily solved by using the law of cosines, which relates the lengths of the sides of a triangle to the cosine of one of its angles.

in this case, the formula can be applied in the following way

a^2 = b^2  + c^2  - 2*b*c*cos(α)

Where

a,b,c are each of the sides of the triangle,

α is the angle between sides b and c

(See attached picture)

If we use the formula we get

a^2 = (9)^2 + (6)^2 - 2*(9)(6)*cos(37°)

a^2 = 81 + 36 - 86.2526

a^2 = 30.747

a = sqrt(30.747)

a = 5.545

5 0
3 years ago
How would you solve this? Are there any steps to take?
Genrish500 [490]
You just have to find what x is. Pretend there isn't the signs and think of it as = signs. Then whatever u do on one side do it to all of them
7 0
3 years ago
Pablo is binging his favorite TV show right before he has to go into work and two hours before he has to go in for his next
liubo4ka [24]

Answer:

b

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Evaluate. (1/6^2)Enter your answer as a fraction in simplest form.​
Papessa [141]

Answer:

1/36

Step-by-step explanation:

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3 0
3 years ago
Someone help I think this is probability but I don’t know
pickupchik [31]

ANSWER

1. 3391680

2. 3876

EXPLANATION

1. We want to find the value of:

P^{12}_7

This is called "12 permutation 7"

Permutation function is defined as follows:

P^n_r\text{ = }\frac{n!}{(n-r)!}

Therefore, we have that:

\begin{gathered} P^{12}_7=\frac{12!}{(12\text{ - 7)}!}\text{ = }\frac{12!}{5!} \\ P^{12}_7=\frac{12\cdot11\cdot10\cdot9\cdot8\cdot7\cdot6\cdot5!}{5!} \\ P^{12}_7=\text{ 12 }\cdot11\cdot10\cdot9\cdot8\cdot7\cdot6 \\ P^{12}_7=3391680 \end{gathered}

2. We want to find:

C^{19}_{15}

This is called "19 combination 15"

Combination function is defined as:

C^n_r=\frac{n!}{(n-r)!\cdot r!_{}}

Therefore, we have that:

\begin{gathered} C^{19}_{15}\text{ = }\frac{19!}{(19-15)!\cdot15!}\text{ = }\frac{19!}{4!\cdot15!} \\ ^{}C^{19}_{15}=\frac{19\cdot18\cdot17\cdot16\cdot15!}{4\cdot3\cdot2\cdot1\cdot15!} \\ C^{19}_{15}=\frac{19\cdot18\cdot17\cdot16}{4\cdot3\cdot2\cdot1} \\ C^{19}_{15}=\text{ 3876} \end{gathered}

7 0
1 year ago
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