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3 years ago

HELP ASAP Solve the equation for x. 3x - 5x + 4 = 10 x = PLEASE ANSWER STEP BY STEP

Mathematics

1 answer:

Doss [256]3 years ago

3 0

Answer:

X=-3

Step-by-step explanation:

3x-5x+4=10

-2x=6

x=-3

note: I wasn’t sure if the equation ended in 10 or 10x. I think it ends at 10 so that is how I solved.

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A particular computer takes 13 minutes to download a 39-minute TV show. How long will it take the computer to download a 2-hou

ZanzabumX [31]

Since 2 hours is 120 minutes, then

$\bf \begin{array}{ccll}
\stackrel{download}{minutes}&\stackrel{show}{minutes}\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
13&39\\
x&120
\end{array}\implies \cfrac{13}{x}=\cfrac{39}{120}\implies \cfrac{13\cdot 120}{39}=x$

5 0

3 years ago

Elephant eats 250 pounds of food every day how many days would it take an elephant to eat a ton of food

ankoles [38]

1 ton= 2,000 pounds

250 x 8 = 2,000

final answer: it would take the elephant 8 days to eat a ton of food

*HOPE I HELPED!*

5 0

3 years ago

10 x 2 tens=_____ Tens = _______

motikmotik

10 × 2 tens = 20 tens = 200

4 0

3 years ago

Read 2 more answers

What is this shape called?

shepuryov [24]

Answer:

This is a triangular prism

Step-by-step explanation:

6 0

4 years ago

A poll shows that 50% of students play sports

Firlakuza [10]

Answer:

The chance of getting a sample proportion of 70% or greater is 0.026.

Step-by-step explanation:

We are given that a poll shows that 50% of students play sports .

A random sample of 20 students showed that 70% of them play sports.

Let $\hat p$ = sample proportion of students who play sports

The z-score probability distribution for the sample proportion is given by;

Z = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of students who play sports = 70%

p = population proportion of students who play sports = 50%

n = sample of students = 20

Now, the chance of getting a sample proportion of 70% or greater is given by = P( $\hat p$ $\geq$ 70%)

P( $\hat p$ $\geq$ 70%) = P( $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ $\geq$ $\frac{0.70-0.50}{\sqrt{\frac{0.70(1-0.70)}{20} } }$ ) = P(Z $\geq$ 1.95) = 1 - P(Z < 1.95)

= 1 - 0.97441 = <u>0.026</u>

The above probability is calculated by looking at the value of x = 1.95 in the z-table which has an area of 0.97441.

Hence, the chance of getting a sample proportion of 70% or greater is 0.026.

8 0

3 years ago