Since you haven't identified this figure, I'm going to assume that it's a rectangle.
The Perimeter of a rectangle of length L and width W is P = 2L + 2W.
Here you are given the Perimeter and the length, and are to find the width, W.
Solving the above equation for W, we get P - 2L = 2W.
Dividing by 2 (to isolate that W), we get
P
-- - L = W
2
Substitute P= 6 yds and L = 6 feet (or 2 yds), find W (in yards).
Using the Pythagorean Theorem, we have x^2+(x+2)^2=51^2, and
x^2+ x^2+4x+4=2x^2+4x+4=51^2. After that, we subtract 51^2 from both sides to get 2x^2+4x-2597. Using the quadratic formula (x=(-b+-sqrt(b^2-4ac))/2a in ax^2+bx+c), we get around 35 for x. We did + instead of minus after b due to that it can't be negative! x+2=37, so you save 35+37-51=around 21 feet
Answer:
b. 1
Step-by-step explanation:
Step 1: Define
y(x) = 4x
y(x) = 4
Step 2: Substitute and Evaluate
4 = 4x
x = 1