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Travka [436]
3 years ago
10

ppppppppppppppppppppppppplllllllllllllllllllllllllllllllllzzzzzzzzzzzzzzzzzzzzzzzz hhhhhhheeeeelllpppppppp

Mathematics
1 answer:
tiny-mole [99]3 years ago
7 0

Answer:

A: 23 5/8

Step-by-step explanation:

Hopefully this helps!

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Does this graph represent a function? Why or why not ?
pashok25 [27]

B. Yes, because it passes the vertical line test.

6 0
3 years ago
Read 2 more answers
Juna travels 15 mph for 10 hours find the distance piles per hour
marta [7]

Answer:2 hours 15 mins = 2 1/4 hours

2 1/4 hours = 25 miles

1 hour = 25 ÷ 2 1/4 = 25 ÷ 9/4 = 25 x 4/9 = 11.1 miles

Answer: 11.1 mph

Step-by-step explanation:

7 0
2 years ago
Complete the solution of the equation. Find the<br> value of y when x equals -14.<br> -2x + 5y = 8
shepuryov [24]

Answer:

y = -4

Step-by-step explanation:

-2x + 5y = 8

Let x=-14

-2(-14) +5y = 8

28 +5y = 8

Subtract 28 from each side

28-28 +5y = 8-28

5y = -20

Divide by 5

5y/5 = -20/5

y = -4

4 0
3 years ago
2x squared + 9x=-5 i need to solve for x
In-s [12.5K]
2x^2+ 9x=-5 \\ \\2x^2 + 9x+5 =0 \\\\a=2, \ \ b=9 , \ \ c=5 \\\\\Delta =b^2-4ac = 9^2 -4\cdot 2\cdot 5 =  81-40=41 \\ \\x_{1}=\frac{-b-\sqrt{\Delta} }{2a}=\frac{-9-\sqrt{41}}{2\cdot 2 }=\frac{-9-\sqrt{41}}{ 4 }\\\\ x_{2}=\frac{-b+\sqrt{\Delta} }{2a}=\frac{-9+\sqrt{41}}{2\cdot 2 }=\frac{-9+\sqrt{41}}{4 }
3 0
3 years ago
This is Matrix for pre calc
gavmur [86]

The given system of equations in augmented matrix form is

\left[\begin{array}{cccc|c}3&2&-4&2&-23\\-6&1&2&4&-12\\1&-3&-3&5&-20\\-2&5&6&0&12\end{array}\right]

If you need to solve this, first get the matrix in RREF:

  • Add 2(row 1) to row 2, row 1 to -3(row 3), and 2(row 1) to 3(row 4):

\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&5&-6&8&-58\\0&11&5&-13&37\\0&19&10&4&-10\end{array}\right]

  • Add 11(row 2) to -5(row 3), and 19(row 1) to -5(row 4):

\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&5&-6&8&-58\\0&0&-91&153&-823\\0&0&-164&132&-1052\end{array}\right]

  • Add 164(row 3) to -91(row 4):

\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&5&-6&8&-58\\0&0&-91&153&-823\\0&0&0&13080&-39240\end{array}\right]

  • Multiply row 4 by 1/13080:

\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&5&-6&8&-58\\0&0&-91&153&-823\\0&0&0&1&-3\end{array}\right]

  • Add -153(row 4) to row 3:

\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&5&-6&8&-58\\0&0&-91&0&-364\\0&0&0&1&-3\end{array}\right]

  • Multiply row 3 by -1/91:

\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&5&-6&8&-58\\0&0&1&0&4\\0&0&0&1&-3\end{array}\right]

  • Add 6(row 3) and -8(row 4) to row 2:

\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&5&0&0&-10\\0&0&1&0&4\\0&0&0&1&-3\end{array}\right]

  • Multiply row 2 by 1/5:

\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&1&0&0&-2\\0&0&1&0&4\\0&0&0&1&-3\end{array}\right]

  • Add -2(row 2), 4(row 3), and -2(row 4) to row 1:

\left[\begin{array}{cccc|c}3&0&0&0&3\\0&1&0&0&-2\\0&0&1&0&4\\0&0&0&1&-3\end{array}\right]

  • Multiply row 1 by 1/3:

\left[\begin{array}{cccc|c}1&0&0&0&1\\0&1&0&0&-2\\0&0&1&0&4\\0&0&0&1&-3\end{array}\right]

So the solution to this system is (w,x,y,z)=(1,-2,4,-3).

6 0
3 years ago
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