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Travka [436]
3 years ago
10

ppppppppppppppppppppppppplllllllllllllllllllllllllllllllllzzzzzzzzzzzzzzzzzzzzzzzz hhhhhhheeeeelllpppppppp

Mathematics
1 answer:
tiny-mole [99]3 years ago
7 0

Answer:

A: 23 5/8

Step-by-step explanation:

Hopefully this helps!

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Please help out and if you know help me show work ??
Ghella [55]

Answer:  14

<u>Step-by-step explanation:</u>

Consecutive even numbers would be {2, 4, 6, 8, 10, ...}

Let x represent the smallest number, then x + 2 is the middle number and x + 4 is the largest number.

1st number: x

2nd number: x + 2

3rd number: x + 4

1st number + 2nd number + 3rd number = Sum

      (x)        +      (x + 2)       +      (x + 4)      =  48

                                                      3x + 6   =  48

                                                      3x          = 42

                                                        x           = 14

1st number: x           ⇒ x = 14

2nd number: x + 2   ⇒ 14 + 2 = 16

3rd number: x + 4    ⇒ 14 + 4 = 18

<u>Check:</u>

14 + 16 + 18 = 48 \checkmark

 

7 0
3 years ago
Please help me on questions 19-21 using this diagram attached
Leona [35]
Vas happenin!!

19. TX
20. O and I can’t see the other bottom of the cube
21. WS
Hope this helps *smiles*
Sorry if it’s wrong
6 0
3 years ago
Which is the graph of y=2/(x+1)-6
krek1111 [17]

Answer:

I have linked the graph in an image

Step-by-step explanation:

1. Simplify  y=2/(x+1)-6

2. Subtract the numbers 1-6=-5

3. = 2/x-5

4. Graph your results

4 0
3 years ago
Read 2 more answers
1. The function h = - 4.9x2 + 40x + 1 gives the height of a baseball after it has been hit
pickupchik [31]
The ball will hit the ground between 8 and 9 seconds

4 0
3 years ago
Hiiii.. please help me with this limit question ​
Alenkasestr [34]

Answer:

π

Step-by-step explanation:

Solving without L'Hopital's rule:

lim(x→0) sin(π cos²x) / x²

Use Pythagorean identity:

lim(x→0) sin(π (1 − sin²x)) / x²

lim(x→0) sin(π − π sin²x) / x²

Use angle difference formula:

lim(x→0) [ sin(π) cos(-π sin²x) − cos(π) sin(-π sin²x) ] / x²

lim(x→0) -sin(-π sin²x) / x²

Use angle reflection formula:

lim(x→0) sin(π sin²x) / x²

Now we multiply by π sin²x / π sin²x.

lim(x→0) [ sin(π sin²x) / x² ] (π sin²x / π sin²x)

lim(x→0) [ sin(π sin²x) / π sin²x] (π sin²x / x²)

lim(x→0) [ sin(π sin²x) / π sin²x] lim(x→0) (π sin²x / x²)

π lim(x→0) [ sin(π sin²x) / π sin²x] [lim(x→0) (sin x / x)]²

Use identity lim(u→0) (sin u / u) = 1.

π (1) (1)²

π

Solving with L'Hopital's rule:

If we plug in x = 0, the limit evaluates to 0/0.  So using L'Hopital's rule:

lim(x→0) [ cos(π cos²x) (-2π cos x sin x) ] / 2x

lim(x→0) [ -π cos(π cos²x) sin(2x) ] / 2x

-π/2 lim(x→0) [ cos(π cos²x) sin(2x) ] / x

Again, the limit evaluates to 0/0.  So using L'Hopital's rule one more time:

-π/2 lim(x→0) [ cos(π cos²x) (2 cos(2x)) + (-sin(π cos²x) (-2π cos x sin x)) sin(2x) ] / 1

-π/2 lim(x→0) [ 2 cos(π cos²x) cos(2x) + π sin(π cos²x) sin²(2x) ]

-π/2 (-2)

π

8 0
3 years ago
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