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2 years ago

What are the coordinates of the terminal point for 6 =330?

Mathematics

1 answer:

Oksi-84 [34.3K]2 years ago

6 0

Answer:

Step-by-step explanation:thank me later

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Total brain fart! 24+5x=-x+6(5a-4)

kow [346]

Answer:

When solving for x, answer = $\large\boxed{x = 5a - 8}$

When solving for a, answer = $\large\boxed{a = 1/5x + 8/5}$

Step-by-step explanation:

24 + 5x = -x + 6(5a - 4)

Start by multiplying 6 by the values in the parenthesis

24 + 5x = -x + 30a - 24

Add 24 to both sides of the equation

48 + 5x = -x + 30a

Add 1x to both sides of the equation

48 + 6x = 30a

Subtract 48 from both sides of the equation

6x = 30a - 48

Divide both sides of the equation by 6

x = 5a - 8 (Answer when solving for x)

Add 8 to both sides of the equation

x + 8 = 5a

Divide both sides of the equation by 5

a = 1/5x + 8/5 (Answer when solving for a)

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When solving for x, answer = $\large\boxed{x = 5a - 8}$

When solving for a, answer = $\large\boxed{a = 1/5x + 8/5}$

Hope this helps :)

3 0

2 years ago

the radius of the base of a right cylinder is 12 cm and the height and the height of the cylinder is 18 cm. in terms of pi what

sladkih [1.3K]

Answer:

Step-by-step explanation:r=12cm,h=18cm,v=?

Vol. Of a cylinder=Πr²h

V= Π×12²×18

V= Π×144×18

V=2592Πcm³

7 0

2 years ago

The number of views in a cat and a dog after they uploaded are represented by the following

alexandr1967 [171]

Answer:

i see nothin

Step-by-step explanation:

5 0

2 years ago

2) f(x) = x2 - 6x +11<br> Degree:<br> Lead Coefficient:<br> End behavior:

Bad White [126]

Answer:

13 - 6 x

Step-by-step explanation:

4 0

2 years ago

Write an equation in slope-intercept form for the line that passes through (4,-3) and is parallel to the line described by y=1/2

Marat540 [252]

Given:

The point, (4, -3)

The line,

$y=\frac{1}{2}x+5$

To find an equation in slope-intercept form for the line that passes through (4,-3) and is parallel to the given line:

The slope of the line is,

$m=\frac{1}{2}$

Since the given line is parallel to the new line, so the slope will be same for the both.

Using the point-slope formula,

$y-y_1=m(x-x_1)$

Substitute the point and slope we get,

$\begin{gathered} y-(-3)=\frac{1}{2}(x-4) \\ y+3=\frac{1}{2}x-2 \\ y=\frac{1}{2}x-2-3 \\ y=\frac{1}{2}x-5 \end{gathered}$

Hence, the equation in slope-intercept form for the line is,

$y=\frac{1}{2}x-5$

8 0

1 year ago