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melisa1 [442]
2 years ago
15

A free body diagram can be used to help work out the net force acting on an object. True or, false?

Physics
1 answer:
Whitepunk [10]2 years ago
6 0

Answer:

free body diagram can be used to help work out the net force acting on an object. True or, false?

Columbian exchange. Tell a story in chronological order of the changes that the community undergoes as it and the communities around it make contact with Europeans over a span of roughly 50 to 100 years.

This section is worth 20 points. See the scoring rubric for more details on how you

will be graded

Use the evidence you gathered to tell the story of a hypothetical indigenous

community in the Americas and its experience involving the Columbian Exchange.

Come up with a community whose circumstances are typical of many in Central

America, the West Indies, or another part of the Americas that had direct contact with

Europeans. Tell the story in chronological order, but feel free to skip whole years or

decades so that you can cover each of the important topics related to the activity: the

availability of goods, the effects of disease, and the impact of European culture

(language and religion, for example), at the very least.

Think of your story as more of a summary than a work of fiction; you must cover a

large span of time in few words. Base the details of the story on factual evidence and

cite your sources, but keep in mind that the text should be written as a story, not as

an essay with a conventional introduction, body, and conclusion. Aim for about 700

to 1,200 words.

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The best rebounders in basketball have a vertical leap (that is, the vertical movement of a fixed point on their body) of about
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Answer:

a) 4.45 m/s

b) 0.9 seconds

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

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v^2-u^2=2as\\\Rightarrow -u^2=2as-v^2\\\Rightarrow u=\sqrt{v^2-2as}\\\Rightarrow u=\sqrt{0^2-2\times -9.81\times 1}\\\Rightarrow u=4.45\ m/s

a) The vertical speed when the player leaves the ground is 4.45 m/s

v=u+at\\\Rightarrow t=\frac{v-u}{a}\\\Rightarrow t=\frac{0-4.45}{-9.81}\\\Rightarrow t=0.45\ s

Time taken to reach the maximum height is 0.45 seconds

s=ut+\frac{1}{2}at^2\\\Rightarrow 1=0t+\frac{1}{2}\times 9.81\times t^2\\\Rightarrow t=\sqrt{\frac{1\times 2}{9.81}}\\\Rightarrow t=0.45\ s

Time taken to reach the ground from the maximum height is 0.45 seconds

b) Time the player stayed in the air is 0.45+0.45 = 0.9 seconds

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A vector must always have both size and ..
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