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goldfiish [28.3K]
3 years ago
5

Match each charged object to the electric field diagram that each would produce?

Physics
1 answer:
LuckyWell [14K]3 years ago
6 0
OK. I see what's going on here.
To answer all of these, you have to know two basic things about the
electric field. 
(THAT's the whole purpose of the question ... to help you determine
whether you're clear on these two things, or need to go over them.)

Thing #1). 
The larger the charge is, the stronger the field is around it,
and a stronger field is indicated with more lines.

Thing #2). 
The direction of the lines is the direction of the force on a tiny positive
charge in the field. 
If the charge in the middle is positive, then another tiny positive charge
gets pushed away from it ... the lines point OUT. 
If the charge in the middle is negative, then a tiny positive charge
gets attracted to it ... the lines point IN.
_________________________

drawing a).
lines point in, charge in the middle is negative
thickest set of lines . . . biggest negative charge

drawing b).
lines point out, charge in the middle is positive
thicker than average lines . . . biggest positive charge

drawing c).
lines point in, charge in the middle is negative
thin lines . . . negative charge in the middle is kind of small

drawing d).
lines point out, charge in the middle is positive
thin lines . . . positive charge in the middle is kind of small
___________________________

I just looked through the charges, to see what they gave us
for positive, negative, big ones, little ones, etc.
BE CAREFUL when you decide which charge to put in the middle.
Don't just look at the beginning numbers ... be sure and consider the exponents too.
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What amount of heat is required to raise the temperature of 25 grams of copper to cause a 15ºC change? The specific heat of copp
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The amount of heat required is B) 150 J

Explanation:

The amount of heat energy required to increase the temperature of a substance is given by the equation:

Q=mC\Delta T

where:

m is the mass of the substance

C is the specific heat capacity of the substance

\Delta T is the change in temperature of the substance

For the sample of copper in this problem, we have:

m = 25 g (mass)

C = 0.39 J/gºC (specific heat capacity of copper)

\Delta T = 15^{\circ}C (change in temperature)

Substituting, we find:

Q=(25)(0.39)(15)=146 J

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What's the difference between mechanical waves and vibrations
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Lucas is carrying his rock collection into class. He carries 30 pounds of rare rocks 15 feet into Classroom 6. It takes him 3 mi
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Read 2 more answers
A ball is thrown downward at 12 m/s from a windowsill 35 m above the ground. At the same time, another ball is thrown upward at
wariber [46]

Answer:

The second ball lands 1.5 s after the first ball.

Explanation:

Given;

initial velocity of the ball, u = 12 m/s

height of fall, h = 35 m

initial velocity of the second, v = 12 m/s

Time taken for the first ball to land;

t = \sqrt{\frac{2h}{g} }\\\\t =\sqrt{ \frac{2*35}{9.8}}\\\\t = 2.67 \ s

determine the maximum height reached by the second ball;

v² = u² -2gh

at maximum height, the final velocity, v = 0

0 = 12² - (2 x 9.8)h

19.6h = 144

h = 144 / 19.6

h = 7.35 m

time to reach this height;

t_1 = \sqrt{\frac{2h}{g} }\\\\t_1 =  \sqrt{\frac{2*7.35}{9.8}}\\\\t_1 = 1.23 \ s

Total height above the ground to be traveled by the second ball is given as;

= 7.35 m + 35m

= 42.35 m

Time taken for the second ball to fall from this height;

t_2 = \sqrt{\frac{2h}{g} }\\\\t_2 = \sqrt{\frac{2*42.35}{9.8} }\\\\t_2 = 2.94 \ s

total time spent in air by the second ball;

T = t₁ + t₂

T = 1.23 s + 2.94 s

T = 4.17 s

Time taken for the second ball to land after the first ball is given by;

t = 4.17 s -  2.67 s

T = 1.5 s

Therefore, the second ball lands 1.5 s after the first ball.

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2 years ago
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