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3 years ago

Write the formula for Gay-Lussac's Law and state what parameters must be kept constant.

Physics

1 answer:

zloy xaker [14]3 years ago

5 0

Gay-Lussac's law k=(P/T)

Explanation:

It is defined as the pressure of a given mass of gas varies directly with the absolute temperature of the gas, where the volume is kept as constant.

This law otherwise called "pressure Law or Dalton's Law".

Mathematical Notation is given as

K=(P/T)

Where,

P- the pressure of a gas

T- Temperature of the gas(in Kelvins)

K- constant

Gay-Lussac's Law is often referred to as pressure-Temperature Law, where if the gas temperature increases, then so do the pressure and volume of the gas is kept constant.

Mathematical Notation is given as

P∝T,

(P/T)=K

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The electrostatic force between the two ions is $2.9\cdot 10^{-10} N$

Explanation:

The electrostatic force between two charged particle is given by Coulomb's law:

$F=k\frac{q_1 q_2}{r^2}$

where

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In this problem, the ion of sodium has a charge of

$q_1 = +e = +1.6\cdot 10^{-19} C$

while the ion of chlorine has a charge of

$q_2 = -e = -1.6\cdot 10^{-19}C$

And the distance between the two ions is

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Substituting, we find the electrostatic force between the two ions:

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6 0

3 years ago

Is my answer correct? Please i need to know

Alexeev081 [22]

Yes. Your answer is correct. I hope you do well on the quiz or whatever it is.

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2 years ago

Read 2 more answers

A 5kg block is pulled across a table by a horizontal force of 40 N with a frictional force of 8 N opposing the motion. Draw a fo

Taya2010 [7]

Answer:

Net force on the block is 32 N.

Acceleration of the object is 6.4 m/s².

Explanation:

Let the acceleration of the object be $a$ m/s².

Given:

Mass of the block is, $m=5\ kg$

Force of pull is, $F=40\ N$

Frictional force on the block is, $f=8\ N$

The free body diagram of the object is shown below.

From the figure, the net force in the forward direction is given as:

$F_{net}=F-f=40-8=32\ N$

Now, from Newton's second law of motion, net force is equal to the product of mass and acceleration. So,

$F_{net}=ma\\32=5a\\a=\frac{32}{5}=6.4\ m/s^2$

Therefore, the acceleration of the object in the forward direction is 6.4 m/s².

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3 years ago

Write the formula for Gay-Lussac's Law and state what parameters must be kept constant.​

Write the formula for Gay-Lussac's Law and state what parameters must be kept constant.