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2 years ago

Write the formula for Gay-Lussac's Law and state what parameters must be kept constant.

Physics

1 answer:

zloy xaker [14]2 years ago

5 0

Gay-Lussac's law k=(P/T)

<u>Explanation</u>:

It is defined as the pressure of a given mass of gas varies directly with the absolute temperature of the gas, where the volume is kept as constant.

This law otherwise called "pressure Law or Dalton's Law".

Mathematical Notation is given as

K=(P/T)

Where,

P- the pressure of a gas

T- Temperature of the gas(in Kelvins)

K- constant

Gay-Lussac's Law is often referred to as pressure-Temperature Law, where if the gas temperature increases, then so do the pressure and volume of the gas is kept constant.

Mathematical Notation is given as

P∝T,

(P/T)=K

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2 years ago

Calculate The voltage if the current passing through the wire is 3A, and has a resistance of 10 Q

Nat2105 [25]

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2 years ago

An airliner arrives at the terminal, and its engines are shut off. The rotor of one of the engines has an initial clockwise angu

Ilia_Sergeevich [38]

(a) 1200 rad/s

The angular acceleration of the rotor is given by:

$\alpha = \frac{\omega_f - \omega_i}{t}$

where we have

$\alpha = -80.0 rad/s^2$ is the angular acceleration (negative since the rotor is slowing down)

$\omega_f$ is the final angular speed

$\omega_i = 2000 rad/s$ is the initial angular speed

t = 10.0 s is the time interval

Solving for $\omega_f$ , we find the final angular speed after 10.0 s:

$\omega_f = \omega_i + \alpha t = 2000 rad/s + (-80.0 rad/s^2)(10.0 s)=1200 rad/s$

(b) 25 s

We can calculate the time needed for the rotor to come to rest, by using again the same formula:

$\alpha = \frac{\omega_f - \omega_i}{t}$

If we re-arrange it for t, we get:

$t = \frac{\omega_f - \omega_i}{\alpha}$

where here we have

$\omega_i = 2000 rad/s$ is the initial angular speed

$\omega_f=0$ is the final angular speed

$\alpha = -80.0 rad/s^2$ is the angular acceleration

Solving the equation,

$t=\frac{0-2000 rad/s}{-80.0 rad/s^2}=25 s$

6 0

3 years ago

Please help ASAP.

Bess [88]

Im not 100% sure you have to tell me if im wrong or not.

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2 years ago

Read 2 more answers

A 100-turn, 3.0-cm-diameter coil is at rest in a horizontal plane. A uniform magnetic field 60%u2218 away from vertical increase

Xelga [282]

Answer:

Induced emf in the coil, E = 0.157 volts

Explanation:

It is given that,

Number of turns, N = 100

Diameter of the coil, d = 3 cm = 0.03 m

Radius of the coil, r = 0.015 m

A uniform magnetic field increases from 0.5 T to 2.5 T in 0.9 s.

Due to this change in magnetic field, an emf is induced in the coil which is given by :

$E=-NA\dfrac{\Delta B}{\Delta t}$

$E=-100\times \pi (0.015)^2\times \dfrac{2.5-0.5}{0.9}$

E = -0.157 volts

Minus sign shows the direction of induced emf in the coil. Hence, the induced emf in the coil is 0.157 volts.

8 0

3 years ago

Write the formula for Gay-Lussac's Law and state what parameters must be kept constant.​

Write the formula for Gay-Lussac's Law and state what parameters must be kept constant.