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butalik [34]
3 years ago
14

An object falls freely from height H. if it takes one second to travel last half of total displacement find height H priop to th

e fall.​
Physics
1 answer:
qaws [65]3 years ago
4 0

Answer:9.82 m

Explanation:

As we know from equation of motion

S=v*t +0.5 a t^2

Know s=H/2

a =9.82

t=1

V=0

Plugging the values

H*0.5=0+0.5*9.82*1^2

H=9.82 m

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2 years ago
Which term describes the quantity of energy transferred from a warmer object to a cooler object?
Mars2501 [29]

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6 0
3 years ago
A mass of 5kg starts from rest and pulls down vertically on a string wound around a disk-shaped, massive pulley. The mass of the
Paha777 [63]

Answer:

c. V = 2 m/s

Explanation:

Using the conservation of energy:

E_i =E_f

so:

Mgh = \frac{1}{2}IW^2 +\frac{1}{2}MV^2

where M is the mass, g the gravity, h the altitude, I the moment of inertia of the pulley, W the angular velocity of the pulley and V the velocity of the mass.

Also we know that:

V = WR

Where R is the radius of the disk, so:

W = V/R

Also, the moment of inertia of the disk is equal to:

I = \frac{1}{2}MR^2

I = \frac{1}{2}(5kg)(2m)^2

I = 10 kg*m^2

so, we can write the initial equation as:

Mgh = \frac{1}{2}IV^2/R^2 +\frac{1}{2}MV^2

Replacing the data:

(5kg)(9.8)(0.3m) = \frac{1}{2}(10)V^2/(2)^2 +\frac{1}{2}(5kg)V^2

solving for V:

(5kg)(9.8)(0.3m) = V^2(\frac{1}{2}(10)1/4 +\frac{1}{2}(5kg))

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8 0
3 years ago
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