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yanalaym [24]
3 years ago
14

Let A={1'3'5'6} B={0'7} check whether A and B are disjoint sets

Mathematics
1 answer:
Setler79 [48]3 years ago
4 0

Given:

The sets are A=\{1,3,5,6\} and B=\{0,7\}.

To find:

Whether A and B are disjoint sets or not.

Solution:

Two sets are called disjoint sets if there are no common elements between them.

We have,

A=\{1,3,5,6\}

B=\{0,7\}

Clearly, there is not common elements between the set A and set B.

Therefore, the sets A and B are disjoint sets.

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What is the equation of the line that passes through the point (-6,-2)and has a slope of 1/6
balu736 [363]

Answer:

y = 1/6x -1

Step-by-step explanation:

Use point-slope form: y - y₁ = m (x - x₁)

y - (-2) = 1/6 (x - (-6))

y + 2 = 1/6x + 1

y = 1/6x - 1

4 0
3 years ago
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How do you do this math problem -4+7x+4=3
11111nata11111 [884]

Answer:

x = 3/7

x = 0.43

Step-by-step explanation:

Make x the subject

x > ×7 > + 4 > -4 = 3

3 > + 4 > -4 > ÷ 7 = x

7 0
3 years ago
I need help I can’t figure it out
dusya [7]

Answer:

\large\boxed{\dfrac{41p}{70q^4(r-9)^2}}

Step-by-step explanation:

\dfrac{2p^4}{5q^5(r-9)^3}\cdot\dfrac{41q(r-9)}{28p^3}\\\\=\dfrac{2\!\!\!\!\diagup^1\cdot41}{5\cdot28\!\!\!\!\!\diagup_{14}}\cdot\dfrac{q\!\!\!\!\diagup}{q^{5\!\!\!\!\diagup^4}}\cdot\dfrac{(r\!\!\!\!\!\!{--}-9)\!\!\!\!\!\!{--}}{(r-9)^{3\!\!\!\!\diagup^2}}\cdot\dfrac{p^{4\!\!\!\!\diagup}}{p^3\!\!\!\!\!\!\diagup}\\\\=\dfrac{41}{70}\cdot\dfrac{1}{q^4}\cdot\dfrac{1}{(r-9)^2}\cdot\dfrac{p}{1}\\\\=\dfrac{41p}{70q^4(r-9)^2}

7 0
3 years ago
A right △ABC is inscribed in circle k(O, r). Find the radius of this circle if:
natta225 [31]

We have been given that a right △ABC is inscribed in circle k(O, r).

m∠C = 90°, AC = 18 cm, m∠B = 30°. We are asked to find the radius of the circle.

First of all, we will draw a diagram that represent the given scenario.

We can see from the attached file that AB is diameter of circle O and it a hypotenuse of triangle ABC.

We will use sine to find side AB.

\text{sin}=\frac{\text{Opposite}}{\text{Hypotenuse}}

\text{sin}(30^{\circ})=\frac{AC}{AB}

\text{sin}(30^{\circ})=\frac{18}{AB}

AB=\frac{18}{\text{sin}(30^{\circ})}

AB=\frac{18}{0.5}

AB=36

Wee know that radius is half the diameter, so radius of given circle would be half of the 36 that is \frac{36}{2}=18.

Therefore, the radius of given circle would be 18 cm.

8 0
3 years ago
The vertices of a triangle are labeled clockwise A(–5, 3), B(6, 1), and C(–2, –3). How could you show that the figure is a right
mafiozo [28]

Explanation:

When the points are plotted on a graph, it is easy to see that the slope of AC is -2 and the slope of BC is 1/2. These slope values have a product of -1, so the corresponding line segments are perpendicular to each other.

___

If you have studied vectors, you can find the dot product of AC with BC:

  AC = (-5, 3) -(-2, -3) = (-3, 6)

  BC = (6, 1) -(-2, -3) = (8, 4)

The dot product is ...

  (-3, 6)·(8, 4) = (-3)(8) + (6)(4) = -24+24 = 0

When the dot product of vectors is zero, they are perpendicular.

5 0
3 years ago
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