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Temka [501]
2 years ago
11

Given that 6.00 Ghanaceasa dolar

Mathematics
1 answer:
mash [69]2 years ago
4 0

Answer:

do you have options to this

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A couple has a 400 acre farm that they want to leave to their future grandchildren. They decide to give each grandchild 12% of t
ruslelena [56]

Answer:

48

Step-by-step explanation:

5 0
2 years ago
What is the inverse of the function f(x) = x +3?
OLga [1]

Answer:

h(x) = x - 3

Step-by-step explanation:

To find the inverse of a function, you can switch the x and y variables.

In f(x) = x + 3, the y variables is "f(x)".

y = x + 3

Now switch the x and y.

x = y + 3

Isolate for y and replace with h(x).

x - 3 = y

y = x - 3

h(x) = x - 3

5 0
2 years ago
Read 2 more answers
URGENT, PLASE HELP! 10pts
Alex73 [517]

Answer:

m(-1)^n - 1

Step-by-step explanation:

5 0
2 years ago
find three consecutive odd integers such that the sum of the smallest number and middle number is 27 less than 3 times the large
katrin2010 [14]

A generic odd number can be written as

2k+1,\quad k \in \mathbb{Z}

Since there is an odd number every two numbers, three consecutive odd numbers will be

2k+1,\quad 2k+3,\quad 2k+5

Now let's make up the equations: the sum of the first two is

(2k+1)+(2k+3)

And 27 less than 3 times the largest is

3(2k+5)-27

These two must be the same, so we have

(2k+1)+(2k+3)=3(2k+5)-27 \iff 4k+4 = 6k+30-27 \iff 4k+4=6k+3

Subtracting 4k and 3 from both sides gives

1=2k \iff k=\dfrac{1}{2}

Which means that the problem has no solution.

To confirm this hypothesis, we can observe that, on the left hand side, we have the sum of two odd numbers, which is even

On the right hand side, we have an odd number, multiplied by 3 (still odd), take away 27 (still odd).

So, the left hand side is even, and the right hand side is odd. They can't be the same number.

7 0
3 years ago
One number is five more than another number. If the square of the smaller number is 3 more than 3 times the larger number, what
11111nata11111 [884]

Answer:

6 and 11

Step-by-step explanation:

n1 = n + 5

ns^2 = 3 + 3nb

6^2 = 3 + 3(11)

36 = 3 + 33

11 = 6 + 5

3 0
1 year ago
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