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mezya [45]
3 years ago
5

Find the solution set of 5/y+4=3/y-2

Mathematics
2 answers:
tiny-mole [99]3 years ago
8 0

Answer:

y = -1/3

Step-by-step explanation:

5/y + 4 = 3/y - 2

5/y - 3/y = - 2 - 4

2/y = -6

y = -1/3

GaryK [48]3 years ago
4 0

Answer:

y=-1/3

Step-by-step explanation:

first combine like terms:

5/y-3/y=-2-4

2/y=-6

now multiply y on both sides:

2=-6y

solve the equation

y=-1/3

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DUDE SOMEONE ANSWER THIS QUESTION
son4ous [18]

The line which rises to the left has slope of -1/3 and y intercept  of 2 so we have

y = -1/3x + 2

3y = -x + 6

x + 3y = 6

Shading is below and the line is  solid so the inequality  is

x + 3y  ≤ 6

The other line has equation

y = 3x - 1

and inequality is

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The answer is B

8 0
3 years ago
Simplify algebraic expression<br> 0.07x+0.11(10,000-x)
Julli [10]

Answer:

1100 - 0.04x

Step-by-step explanation:

0.07x + 0.11(10,000 - x)

0.07x - 0.11x +1100

-0.04x + 1100

4 0
3 years ago
In a certain Algebra 2 class of 25 students, 13 of them play basketball and 11 of them play baseball. There are 4 students who p
Flauer [41]

Answer:

\frac{4}{5}

Step-by-step explanation:

Given: There are 2 classes of 25 students.

            13 play basketball

            11 play baseball.

            4 play neither of sports.

Lets assume basketball as "a" and baseball as "b".

We know, probablity dependent formula; P(a∪b)= P(a)+P(b)-p(a∩b)

As given total number of student is 25

Now, subtituting the values in the formula.

⇒P(a∪b)= \frac{13}{25} +\frac{11}{25} -\frac{4}{25}

taking LCD as 25 to solve.

⇒P(a∪b)= \frac{13\times 1+11\times 1-4\times 1}{25} = \frac{20}{25}

∴ P(a∪b)= \frac{4}{5}

Hence, the probability that a student chosen randomly from the class plays both basketball and baseball is \frac{4}{5}.

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The vertex of y= 22 - 82 +18 is
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The vertex to the equation is, (4,2)
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