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GaryK [48]
2 years ago
7

Someone plzzz helppp? I need this it’s 8th grade mathh

Mathematics
1 answer:
umka21 [38]2 years ago
4 0
Y = 10x + 5.

the total cost of canoe renting is $10 per hour plus a $5 daily rate
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Which statement best explains why the graphed relation is not a function?
shusha [124]

Answer:

c

Step-by-step explanation:

Because you can't have multiple x-values. You can only have multiple y-values.

4 0
2 years ago
Write a 4 digit number that has no zeroes and is divisible by 5 and 9
Hunter-Best [27]

Answer:

7,515

Step-by-step explanation:

8 0
3 years ago
Which is the graph of g(x) = [X + 3]?
Rudik [331]

Step-by-step explanation:

g(x) = [X + 3]? the answer is 1 =3x

6 0
2 years ago
How many strings can be formed by ordering the letters MISSISSIPPI which
Mazyrski [523]

Answer:

<em>1680 is the answer.</em>

Step-by-step explanation:

Here, we have 11 letters in the word <em>MISSISSIPPI.</em>

Repetition of letters:

M - 1 time

I - 4 times

S - 4 times

P - 2 times

As per question statement, we need a substring MISS in the resultant strings.

So, we need to treat MISS as one unit so that <em>MISS always comes together in all the strings</em>.

The resultant strings will look like:

<em>xxxxMISSxxx</em>

<em>xxMISSxxxxx</em>

<em>and so on.</em>

After we treat <em>MISS </em>as one unit, total letters = 8

Repetition of letters:

MISS - 1 time

I - 3 times

S - 2 times

P - 2 times

The formula for combination of letters with total of <em>n </em>letters:

\dfrac{n!}{p!q!r!}

where <em>p, q</em> and <em>r</em> are the number of times other letters are getting repeated.

<em>p = 3</em>

<em>q = 2</em>

<em>r = 2</em>

<em></em>

So, required number of strings that contain MISS as substring:

\dfrac{8!}{3!2!2!}\\\Rightarrow \dfrac{40320}{6\times 2 \times 2}\\\Rightarrow 1680

So, <em>1680 is the answer.</em>

3 0
2 years ago
A board game has a spinner divided into sections of equal size. Each section is labeled with a number between 1 and 5.
Evgesh-ka [11]

Answer:

30 times

Step-by-step explanation:

1. find the possibility of the spinner landing on each section

<em>1 / 5 = 0.2</em>

<em />

2. multiply # of spins by the possibility

<em>150 * 0.2 = </em><em><u>30 times</u></em>

4 0
2 years ago
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