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2 years ago

Someone plzzz helppp? I need this it’s 8th grade mathh

Mathematics

1 answer:

umka21 [38]2 years ago

4 0

Y = 10x + 5.

the total cost of canoe renting is $10 per hour plus a $5 daily rate

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A number whose value is greater than zero

Dima020 [189]

Answer:

natural number

Step-by-step explanation:

natural number

6 0

1 year ago

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The value of n. 3n = (3^2)8

cupoosta [38]

Answer:

n= 24

because 3*24=72

and (3^2)8 = 9*8=72

8 0

2 years ago

a textbook company ships its books in boxes that can hold 30 pounds. one particular order calls for a shipment of 800 books. if

Pachacha [2.7K]

83 boxes are required to carry 800 books.

According to the question:

One Box can hold weight = 30 pounds

We know that , 1 pound= 0.45 kg

hence, 30 pounds = 30 x 0.45 = 13.5kg

hence, one box can carry 13.5 kg of weight.

Now,

Weight of 1 book = 1.4 kg

So, Total Weight of 800 books= 1.4 x 800 kg

And , No. of boxes required to carry 800 books = (1.4 x 800)/13.5 = 82.96

or approximately 83 boxes

Hence, 83 boxes are required to carry 800 books.

Learn more about Unitary Method at :

brainly.com/question/19423643

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4 0

1 year ago

85 x 63 whoever gets it gets braiest

Katena32 [7]

<span>85 x 63 = 5355

hope it helps

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6 0

3 years ago

Read 2 more answers

A Simple random sample of 100 8th graders at a large suburban middle school indicated that 84% of them are involved with some ty

Setler [38]

Answer: a) (0.755, 0.925)

Step-by-step explanation:

Let p be the population proportion of 8th graders are involved with some type of after school activity.

As per given , we have

n= 100

sample proportion: $\hat{p}=0.84$

Significance level : $\alpha= 1-0.98=0.02$

Critical z-value : $z_{\alpha/2}=2.33$ (using z-value table)

Then, the 98% confidence interval that estimates the proportion of them that are involved in an after school activity will be :-

$\hat{p}\pm z_{\alpha/2}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}$

i.e. $0.84\pm (2.33)\sqrt{\dfrac{0.84(1-0.84)}{100}}$

i.e. $\approx0.84\pm 0.085$

i.e. $(0.84- 0.085,\ 0.84+ 0.085)=(0.755,\ 0.925)$

Hence, the 98% confidence interval that estimates the proportion of them that are involved in an after school activity : a) (0.755, 0.925)

3 0

3 years ago