when given SAS, the area (A) of the triangle = (side1 · sin θ · side2)/2
A = (36 · sin 45° · 36)/2
= (36² · √2)/4
= 9 · 36 · √2
= 324√2
≈ 458.2
The probability of getting all heads is 1 / 2^6 = 1/64 as there is only 1 event where this happens in a possible 2^6 = 64 events. It is the same as the probability of getting all tails. The probability of getting at least 1 head is 1 - p(all tails) = 63/64.
Its (x+1−√<span><span><span><span>5</span><span></span></span>ı)(x+1+<span>√<span><span>5</span><span></span></span></span>ı)</span><span>
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This is a common multiplication problem. Imagine P(4) as x, and Q(4) as y. You are plugging them into the equation x*y. Since x is equal to 13, and y is equal to 8, you are going to plug them into their corresponding variables and multiply. 13 * 8 = 104. The answer is 104.
