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Alex777 [14]
3 years ago
12

5 x 7 + 14 x / 7 - 35

Mathematics
2 answers:
fiasKO [112]3 years ago
7 0

Answer:

46 .....................then 7

Masteriza [31]3 years ago
3 0

Answer:2x

Step-by-step explanation:

You might be interested in
Find the approximate perimeter of rectangle ABCD plotted below. B(4,5) AC -6,0) C(8,-3) D(-2,-8) Choose 1 answer: Do 5 problems
Likurg_2 [28]

Answer:

Perimeter of rectangle ABCD = 47.62

Step-by-step explanation:

The perimeter of a rectangle is P = 2(length + width)

You need to find length and width

If you graph, you can pick your length length and your width

Pick two points after you graph, for (x_{1},y_{1})  and (x_{2},y_{2})

Use the distance formula to find the length =\sqrt{(x_{2} - x_{1} )^{2} + (y_{2} - y_{1} ^{2})}

point B (4,5) will be point 1 and point C (8,-3) will be point 2

Substitute

length =\sqrt{(8 - 4 )^{2} + (-3- 5 )^{2}}\\

length = \sqrt{80}

length = 8.94

Use the distance formula to find the width =\sqrt{(x_{2} - x_{1} )^{2} + (y_{2} - y_{1} ^{2})}

point C (8,-3) will be point 1 and point D (-2,8) will be point 2

Substitute

width =\sqrt{(-2 - 8 )^{2} + (8- (-3) )^{2}}\\

width =\sqrt{(-10 )^{2} + (11 )^{2}}\\

width =\sqrt{100 + 121}\\

width = \sqrt{221}

width = 14.87

Now use formula P = 2(length + width)

P = 2(8.94 + 14.87)

Perimeter of rectangle ABCD = 47.62

7 0
3 years ago
What is 4/5 of 20.5?
ira [324]
16.4
20.5/5=4.1
4.1*4=16.4 
............
7 0
3 years ago
Question below asap please.
docker41 [41]
Function number one , the graphing seems good
8 0
2 years ago
Find the sum.<br> 5+ (-7)
vazorg [7]

Answer:

-2

Step-by-step explanation:

5 + (-7)

5 - 7

-2

Please let me know if something's wrong!

5 0
3 years ago
13.......................
Alla [95]

Answer:

The answer is (d) ⇒ pq^{2}r\sqrt[3]{pr^{2}}

Step-by-step explanation:

* To simplify the cube roots:

 If its number then the number must be written in the form x³

 then we divide the power by 3 to cancel the radical

 If its variable we divide its power by 3 to cancel the radical

∵ \sqrt[3]{p^{4}q^{6}r^{5}}=p^{\frac{4}{3}}q^{\frac{6}{3}}r^{\frac{5}{3}}}

∴ p^{\frac{4}{3}}q^{2}}r^{\frac{5}{3}}=p^{1\frac{1}{3}}q^{2}r^{1\frac{2}{3}}

∵ p^{\frac{1}{3}}=\sqrt[3]{p}

∵ r^{\frac{2}{3}}=\sqrt[3]{r^{2}}

∴ p(p)^{\frac{1}{3}}q^{2}r(r)^{\frac{2}{3}}=p(\sqrt[3]{p})q^{2}r(\sqrt[3]{r^{2}})

∴ prq^{2}\sqrt[3]{pr^{2}}}

∴ The answer is (d)

5 0
3 years ago
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