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AysviL [449]
3 years ago
12

Find the common difference of the arithmetic sequence, the next three terms, the equation, and the term given for 8, 10, 12, 14

Mathematics
1 answer:
fredd [130]3 years ago
5 0

Answer:

see explanation

Step-by-step explanation:

In an arithmetic sequence the common difference d is

d = a₂ - a₁ = 10 - 8 = 2

To obtain the next term in the sequence add d to the previous term, that is

a₅ = 14 + 2 = 16

a₆ = 16 + 2 = 18

a₇ = 18 + 2 = 20

The next 3 terms in the sequence are 16, 18, 20

The n th term equation for an arithmetic sequence is

a_{n} = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Here a₁ = 8 and d = 2, thus

a_{n} = 8 + 2(n - 1) = 8 + 2n - 2 = 2n + 6

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Write a polynomial function f of least degree that has rational coefficients, a leading coefficient of 1, and the zeros −3 and 5
love history [14]

Answer:

<em>f(x) = x² (2+i)x-15-3i</em>

Step-by-step explanation:

Since the zeros of the equation are -3 and 5+i, hence the factors of the polynomial in x is (x+3) and (x-(5+i))

Multiplying both factors

f(x) =  (x+3)(x-(5+i))

f(x) = (x²-(5+i)x+3x -3(5+i))

f(x) = x² - (5+i- 3)x -15-3i

f(x) = x² (2+i)x-15-3i

<em>hence the required polynomial function in x is f(x) = x² (2+i)x-15-3i</em>

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3 years ago
Find the area of the triangle
Cerrena [4.2K]

Answer:

Part 1)  P=204\ yd

Part 2) A=1,325\ yd^2

Step-by-step explanation:

Part 1)

we know that

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so

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Part 2)

we know that

The area of triangle is given by the formula

A=\frac{1}{2}(b)(h)

we have

b=53\ yd\\h=50\ yd

substitute

A=\frac{1}{2}(53)(50)=1,325\ yd^2

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A right scalene is the answer
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Consider the equation x^2=36
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