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3 years ago

Find the value of x for which ABCD must be a parallelogram.

Mathematics

1 answer:

Korvikt [17]3 years ago

8 0

Answer:

$x = \frac{5}{3}$

Step-by-step explanation:

Parallelogram

It's a quadrilateral formed by two pairs of parallel sides. The opposite sides have equal lengths.

We are given a parallelogram with opposite sides of 3x+1 and 6x-4. They must be equal, thus:

6x - 4 = 3x + 1

Subtracting 3x:

3x - 4 = 1

Adding 4:

3x = 5

Dividing by 3:

$\mathbf{x = \frac{5}{3}}$

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An equilateral triangle ΔLMQ (see picture to the right) is drawn in the interior of square LMNP so that side is common. Find m∠L

lesya692 [45]

I don’t see the picture if I see it I can help you tho

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3 years ago

(sin x)(tan x cos x - cot x cos x) = 1 - 2 cos2x

Aliun [14]

As

$\tan x=\dfrac{\sin x}{\cos x}$
$\cot x=\dfrac{\cos x}{\sin x}$

we have

$\sin x(\tan x\cos x-\cot x\cos x)=\sin x\left(\sin x-\dfrac{\cos^2x}{\sin x}\right)=\sin^2x-\cos^2x$

Recalling that $\cos2x=\cos^2x-\sin^2x$ , we end up with

$-\cos2x=1-2\cos2x$
$1=\cos2x$
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(where $n$ is any integer)

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3 years ago

Order 74.585, 74.586, 74.486, and 74.587 in decreasing order.

Veseljchak [2.6K]

Answer:

74.587, 74.586, 74.585, 75.486

Step-by-step explanation:

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6 0

2 years ago

Read 2 more answers

Encuentre el punto medio entre (-4, 4) y (-2, 2).

Nata [24]

Answer:

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Step-by-step explanation:

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3 years ago

What is the slope of a line that is parallel to the line -6y=8x-4?

lesya692 [45]

Answer:

-4

Step-by-step explanation:

-6y=8x-4

0=8x+6y-4---(i)

slope (m1)=-coefficient of x

coefficient of y

=-8

= -4

As the lines are parallel,

m1=m2

so,

The slope of line parallel to the line having equation -6y=8x-4 is -4

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3 years ago