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melomori [17]
3 years ago
5

The sum of the polynomial x^3+7x^2+8 and the product of the polynomials x^2–6x+4 and x–1

Mathematics
2 answers:
Diano4ka-milaya [45]3 years ago
8 0
I am also not sure, because I also asked this question.

kipiarov [429]3 years ago
7 0

We have been asked to simplify

(x^3+7x^2+8)+(x^2-6x+4)(x-1)\\ \\ \text{First multiply the terms inside the parenthesis using FOIL we get}\\ \\ =(x^3+7x^2+8)+(x^3-6x^2+4x-x^2+6x-4)\\ \\ \text{Re-write the like terms together and simplify  we get}\\ \\ =(x^3+7x^2+8)+(x^3-7x^2+10x-4)\\ \\ =x^3+7x^2+8+x^3-7x^2+10x-4\\ \\ \text{Add the like terms together again and simplify we get}\\ \\ =2x^3+10x+4\\

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(a) Use the fundamental theorem of algebra to determine the number of roots for 2x^2 + 4x + 7
zysi [14]

Answer:

Step-by-step explanation:

A 2nd order polynomial such as this one will have 2 roots; a 3rd order polynomial 3 roots, and so on.

The quadratic formula is one of the faster ways (in this situation, at least) in which to find the roots.  From 2x^2 + 4x + 7 we get a = 2, b = 4 and c = 7.

Then the discriminant is b^2 - 4ac, or, here, 4^2 - 4(2)(7), or -40.  Because the discriminant is negative, we know that the roots will be complex and unequal.

Using the quadratic formula:

       -4 ±√[-40]         -4 ± 2i√10

x  = ------------------ = ------------------

                4                       4

                                       -2 ± i√10

Thus, the roots are x = ------------------

                                               2

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3 years ago
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leonid [27]

Answer:

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Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
(12x5+3x25)-8<br><br> 12x5=60<br> 3x25=75<br> 60+75=135<br> 135-8=127
lions [1.4K]

Answer:

127

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Please answer correctly !!!!!!!!! Will<br> Mark brainliest !!!!!!!!!!!!!
il63 [147K]

Answer:

x=-\frac{-20+\sqrt{-20w+3600}}{10},\:x=-\frac{-20-\sqrt{-20w+3600}}{10}

Step-by-step explanation:

w=-5\left(x-8\right)\left(x+4\right)\\\mathrm{Expand\:}-5\left(x-8\right)\left(x+4\right):\quad -5x^2+20x+160\\w=-5x^2+20x+160\\Switch\:sides\\-5x^2+20x+160=w\\\mathrm{Subtract\:}w\mathrm{\:from\:both\:sides}\\-5x^2+20x+160-w=w-w\\Simplify\\-5x^2+20x+160-w=0\\Solve\:with\:the\:quadratic\:formula\\\mathrm{Quadratic\:Equation\:Formula:}\\\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

\mathrm{For\:}\quad a=-5,\:b=20,\:c=160-w:\quad x_{1,\:2}=\frac{-20\pm \sqrt{20^2-4\left(-5\right)\left(160-w\right)}}{2\left(-5\right)}\\x=\frac{-20+\sqrt{20^2-4\left(-5\right)\left(160-w\right)}}{2\left(-5\right)}:\quad -\frac{-20+\sqrt{-20w+3600}}{10}\\x=\frac{-20-\sqrt{20^2-4\left(-5\right)\left(160-w\right)}}{2\left(-5\right)}:\quad -\frac{-20-\sqrt{-20w+3600}}{10}\\The\:solutions\:to\:the\:quadratic\:equation\:are\\x=-\frac{-20+\sqrt{-20w+3600}}{10},\:x=-\frac{-20-\sqrt{-20w+3600}}{10}

6 0
3 years ago
What does the expression n+3 represent?
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Do you know what n equals so i can solve it?<span />
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