1) x^2=36
x=6
3) x^2-8x+13=0 —> x= (8±√64-4(1)(13))/2(1)
x=4±√3
5) x^2-6x+9-k=0 —> x=(6±√36-4(1)(9-k))/2(1) —> (6±√4k)/2 —> (6±2√k)/2
x=3±√k
7) y=x^2-4x+11 —> y-11=x^2-4x —> take the half of the coefficient of the single x term and square it and add it on both sides —> y-11+4=x^2-4x+4 —> y-7=(x-2)^2 —> y=(x-2)^2+7
Minimum: (2,7)
Maximum: n/a
X intercepts: none (never crosses the x-intercept)
9) y=x^2+2x-8 —> y+8+1=x^2+2x+1 —> y=(x+1)^2-9
Minimum: (-1,-9)
Maximum: n/a
x-intercepts: (x+4)(x-2) —> (-4,0),(2,0)
11) c
13) (x+7)(x+3)
15) x=(-6±√36-4(1)(10))/2 —> x=(-6±√-4)/2 —> (-6±2i)/2
x=-3±i OR no real solutions
what is the problem? it might help to see it
The total combinations of 5 numbers that can be made from
59 numbers is:
59C5 = 5,006,386
So the probability of winning is:
P = 1 / 5,006,386
P = 1.997 x 10^-7
So the expected payoff is:
P = $1,000,000 (1.997 x 10^-7) - $1 (1 - 1.997 x 10^-7)
<span>P = - $0.80 (loss)</span>
<span>
</span>
<span>D</span>
Answer:
11x + 3=3 is 11/11
Step-by-step explanation:
Answer:
The legs are 5cm and 10cm
Step-by-step explanation:
= 
+ 
125 = 
25 =
x = 5 shorter side
2x=10 longer side
