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LekaFEV [45]
2 years ago
5

PLS HELP PLS I DONT FEEL LIKE DOING IT BRAIN IF CORRECT DUE RIGHT NOW

Mathematics
2 answers:
Vikentia [17]2 years ago
8 0

Answer:

See Below

Step-by-step explanation:

1) 180 ft / 6 sec

To find a unit rate, you need to have a denominator of 1 and to to do that, you can divide the numerator and denominator by the same number, in this case: 6.

30 ft / 1 sec

2) 86 mi / 5 hr

Same as above^(except dividing by 5)

17.2 mi / 1 hr

3) 83 mi / 5 hr

Same as above^^

16.6 mi / 1 hr

We can rewrite this as: 16.6 mph

4) 93 mi / 5 hr

Same as above^^^

18.6 mi / 1 hr

5) 150 mi / 4 hr

Same as above^^^^

37.5 mi / 1 hr

We can rewrite this as: 37.5 mph

Kaylis [27]2 years ago
6 0

Answer:

1) 180 ft / 6 sec

To find a unit rate, you need to have a denominator of 1 and to to do that, you can divide the numerator and denominator by the same number, in this case: 6.

30 ft / 1 sec

2) 86 mi / 5 hr

Same as above^(except dividing by 5)

17.2 mi / 1 hr

3) 83 mi / 5 hr

Same as above^^

16.6 mi / 1 hr

We can rewrite this as: 16.6 mph

4) 93 mi / 5 hr

Same as above^^^

18.6 mi / 1 hr

5) 150 mi / 4 hr

Same as above^^^^

37.5 mi / 1 hr

We can rewrite this as: 37.5 mph

Step-by-step explanation:

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Step-by-step explanation:

4 0
2 years ago
Marine fuel is a combination of gasoline and motor oil. The standard gasoline and oil mixture is about 98% gasoline and about 2%
Georgia [21]

Answer:

0.98g+ 0.02m= 7.1224 gallons standard mixture

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Step-by-step explanation:

If we have to use 6 gallons of gasoline this means that 98%= 6 gallons and 2% would be 6/98*2

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6              :    x

98        : 2

Using the product rule

x= 6*2/98= 0.1224 gallons of motor oil is required.

Let the gasoline be represented by g and motor oil by m then for the standard oil the equation would be

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For break in oil

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Using the product rule

x= 6*4/96= 0.25 gallons of motor oil is required.

Let the gasoline be represented by g and motor oil by m then for the break oil the equation would be

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96% of the 4 gallons of the "break in" mixture is gasoline =  3.84 gallons of gasoline

4% of 4 = 0.16 gallons of motor oil

Now the standard mixture 4 gallons would contain 98 % of gasoline and 2 % of motor oil

98% of 4 gallons= 3.92 gallons of gasoline

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6 0
2 years ago
Rotation 180 counterclockwise around the origin of the point (-3,-7)
yaroslaw [1]

Answer: (3 , 7)

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8 0
2 years ago
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