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Paladinen [302]
3 years ago
10

Try one last time

Mathematics
1 answer:
Ierofanga [76]3 years ago
3 0

Answer:

$144

Step-by-step explanation:

divide 272 by 17 and then multiply that answer by 9

272/17 is 16

so 16 dollars an hour

multiply that by 9

you get 144

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You are paid $82.50 for 7 1/2 hours of work, whats is your rate of pay?
ra1l [238]

Answer:

Rate of Pay is $11 per hour.

Step-by-step explanation:

Cost of 7\frac{1}{2}\:hr of work = $ 82.50

To find: Rate of pay

Here Rate of Pay means Cost of 1 hour of work or we can say cost of per hour work.

7\frac{1}{2}=\frac{7\times2+1}{2}=\frac{15}{2}

⇒ Cost of \frac{15}{2}\;hr of work = $ 82.50

Cost of 1 hr of work = \frac{82.50}{\frac{15}{2}}

                                = \frac{82.50\times2}{15}

                                = \frac{165}{15}

                                = $ 11

Therefore, Rate of Pay is $11 per hour.

5 0
3 years ago
Read 2 more answers
22/5 times 2 times 1/3
LUCKY_DIMON [66]

Answer:

44/15 or maybe 2 14/15

Step-by-step explanation:

4 0
3 years ago
When csc(O)sin(0) is simplified, what is the result?
Olin [163]

Answer:

This is not my answer, it was done by another expert in Brainly.

We are given:  

csc (0) * sin (0)  

This is to be simplified using trigonometric identities:  

csc (x) = 1/sin(x)  

so, csc (0) = 1/sin(0)  

then,  

1/sin(0) * sin (0), the result will be sin(0) / sin (0) which is equal to 1.  

Therefore, the answer is 1.

3 0
2 years ago
How many solutions does the following equation have?<br><br> 3x + 6 = 3(x + 2)
kow [346]
3x+6=3(x+2)
3x+6=3x+6
minus 6 both sides
3x=3x
divide by 3
x=x

true

therefor all numbers work for x

there are infinite soltuions
8 0
3 years ago
g A program executes a mix of different instruction types. 25% of the instructions require two clock cycles to execute, 20% requ
Tomtit [17]

Answer:

1.8 cycles

Step-by-step explanation:

The average number of clock cycles per instruction is given by the sum of the product of each possible number of cycles by its likelihood.

1 cycle: 50%

2 cycles : 25%

3 cycles : 20%

4 cycles : 5%

Avg = 0.5*1+0.25*2+0.20*3+0.05*4\\Avg= 1.8\ cycles

The average number of clock cycles per instruction is 1.8.

8 0
3 years ago
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