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sladkih [1.3K]
2 years ago
11

Help mee plz if you r wrong i will tell slenderman to come and get u

Mathematics
1 answer:
Ivanshal [37]2 years ago
3 0

Answer: it’s -5/2 I think. You might have to dive idea if it doesn’t let you put the fraction, but that is the rise over run or y over x

Step-by-step explanation:

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What is equivalent to 2:6
Katena32 [7]


HI,THE ANSWER TO YOUR PROBLEM IS 1:3

HOPE THIS HELPED! D:



8 0
3 years ago
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Evaluate the expression,<br> if x = 9, y = 3, and z = 5.<br> z²(x - y)
EastWind [94]
The answer is 150.
(5)^2(9-3)
25(6)
=150
3 0
1 year ago
2. Gerald was given the following problem to solve for the length of the "?". He has made a mistake in his work.
Degger [83]

Answer:

x = 18.7

Step-by-step explanation:

Gerald's answer is almost correct.  

He just needs to switch the 14 and the x.

it should be

24/x = 18/14

solve for x by cross multiplication

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18x = 336

x = 18.7

5 0
2 years ago
Evaluate the iterated integral. $$ \int\limits_0^{2\pi}\int\limits_0^y\int\limits_0^x {\color{red}9} \cos(x+y+z)\,dz\,dx\,dy $$
KengaRu [80]
\displaystyle\int_{y=0}^{y=2\pi}\int_{x=0}^{x=y}\int_{z=0}^{z=x}\cos(x+y+z)\,\mathrm dz\,\mathrm dx\,\mathrm dy=\int_{y=0}^{y=2\pi}\int_{x=0}^{x=y}\sin(x+y+z)\bigg|_{z=0}^{z=x}\,\mathrm dx\,\mathrm dy
\displaystyle=\int_{y=0}^{y=2\pi}\int_{x=0}^{x=y}\sin(2x+y)-\sin(x+y)\,\mathrm dx\,\mathrm dy
\displaystyle=\int_{y=0}^{y=2\pi}-\frac12\left(\cos(2x+y)-2\cos(x+y)\right)\bigg|_{x=0}^{x=y}\,\mathrm dx\,\mathrm dy
\displaystyle=\int_{y=0}^{y=2\pi}-\frac12\left((\cos3y-2\cos2y)-(\cos y-2\cos y)\right)\bigg|_{x=0}^{x=y}\,\mathrm dy
\displaystyle=-\frac12\int_{y=0}^{y=2\pi}(\cos3y-2\cos2y+\cos y)\,\mathrm dy
\displaystyle=-\frac12\left(\frac13\sin3y-\sin2y+\sin y\right)\bigg|_{y=0}^{y=2\pi}
=0
4 0
3 years ago
A new teen magazine has a readership goal of 3.5 million. It's current readership is 2.8 million. How much does its readership n
Kazeer [188]

3,500,000 - 2,800,000 = 700,000

So the magazine needs 700,000 readers to meet their goal.

Hope that helps you. :-)

6 0
3 years ago
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