Question

Find z such that 4.8% of the standard normal curve lies to the left of z. (Round your answer to two decimal places)

Answer 1

Answer:

The correct answer will be "-1.66".

Step-by-step explanation:

Let z₀ be,

$P(z$

                $=0.048$

⇒ $\Phi (z_0)=0.048$

Now,

⇒ $\Phi (-1.6646)=0.048$

   $z_0=-1.6646$

       $\simeq -1.66$

Thus the above is the right answer.