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yKpoI14uk [10]
3 years ago
15

Write a recursive function next_pow2(n) that returns the smallest integer value p such that for a non-negative value n. For exam

ple: function call return value next_pow2(0) 0 next_pow2(1) 0 next_pow2(2) 1 next_pow2(3) 2 next_pow2(4) 2 next_pow2(5) 3 next_pow2(6) 3 next_pow2(7) 3 next_pow2(8) 3 next_pow2(9) 4 next_pow2(255) 8 next_pow2(256) 8 next_pow2(257) 9
Computers and Technology
1 answer:
Finger [1]3 years ago
8 0

Answer:

Explanation:

The following code is written in Python and is a recursive function as requested that uses the current value of p (which is count in this instance) and raises 2 to the power of p. If the result is greater than or equal to the value of n then it returns the value of p (count) otherwise it raises it by 1 and calls the function again.

def next_pow2(n, count = 0):

   if (2**count) < n:

       count += 1

       return next_pow2(n, count)

   else:

       return count

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What are new technologies, products, or services that eventually surpass the existing dominant technology or product in a market
kicyunya [14]

Answer:

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3 years ago
write a 2d array c program that can capture marks of 15 students and display the maximum mark, the sum and average​
bekas [8.4K]

Answer:

#include <stdio.h>  

int MaxMark(int* arr, int size) {

   int maxMark = 0;

   if (size > 0) {

       maxMark = arr[0];

   }

   for (int i = 0; i < size; i++) {

       if (arr[i] > maxMark) {

           maxMark = arr[i];

       }

   }

   return maxMark;

}

int SumMarks(int* arr, int size) {

   int sum = 0;

   for (int i = 0; i < size; i++) {

       sum += arr[i];

   }

   return sum;

}

float AvgMark(int* arr, int size) {

   int sum = SumMarks(arr, size);

   return (float)sum / size;

}

int main()

{

   int student0[] = { 7, 5, 6, 9 };

   int student1[] = { 3, 7, 7 };

   int student2[] = { 2, 8, 6, 1, 6 };

   int* marks[] = { student0, student1, student2 };

   int nrMarks[] = { 4, 3, 5 };

   int nrStudents = sizeof(marks) / sizeof(marks[0]);

   for (int student = 0; student < nrStudents; student++) {              

       printf("Student %d: max=%d, sum=%d, avg=%.1f\n",  

           student,

           MaxMark(marks[student], nrMarks[student]),

           SumMarks(marks[student], nrMarks[student]),

           AvgMark(marks[student], nrMarks[student]));

   }

   return 0;

}

Explanation:

Here is an example using a jagged array. Extend it to 15 students yourself. One weak spot is counting the number of marks, you have to keep it in sync with the array size. This is always a problem in C and would better be solved with a more dynamic data structure.

If you need the marks to be float, you can change the types.

3 0
3 years ago
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