Answer:
D. x <= -3 or x >= 5
Step-by-step explanation:
3 | x-1 | > = 12
3(x - 1) >= 12
3x - 3 >= 12
3x >= 15
x >= 5
or
-3(x - 1) >= 12
-3x + 3 >= 12
-3x >= 9
x <= -3
Answer
x <= -3 or x >= 5
Answer: Integer
Step-by-step explanation: The answer would be integer
Answer:
The answer is 10m + 7n - 14
Step-by-step explanation:
Q = 7m + 3n
R = 11 - 2m
S = n + 5
T = -m - 3n + 8
[Q - R] + [S - T] is
[ 7m + 3n - (11 - 2m) ] + [ n + 5 - ( - m - 3n+8)]
Solve the terms in the bracket first
That's
( 7m + 3n - 11 + 2m ) + ( n + 5 + m + 3n - 8)
( 9m + 3n - 11 ) + ( m + 4n - 3)
<u>Remove the brackets</u>
That's
9m + 3n - 11 + m + 4n - 3
<u>Group like terms</u>
9m + m + 3n + 4n - 11 - 3
The final answer is
<h3>
10m + 7n - 14</h3>
Hope this helps you
to find the distance between 2 points we should apply the formula
![d=\sqrt[]{(x_2-x_1)^2+(y_2-_{}y_1)^2_{}}](https://tex.z-dn.net/?f=d%3D%5Csqrt%5B%5D%7B%28x_2-x_1%29%5E2%2B%28y_2-_%7B%7Dy_1%29%5E2_%7B%7D%7D)
call point q as point 1 for reference in the formula and p as point 2
replace the coordinates in the formula
![d=\sqrt[]{(3-(-1))^2+(-4-(-1))^2}](https://tex.z-dn.net/?f=d%3D%5Csqrt%5B%5D%7B%283-%28-1%29%29%5E2%2B%28-4-%28-1%29%29%5E2%7D)
simplify the equation
![\begin{gathered} d=\sqrt[]{(3+1)^2+(-4+1)^2} \\ d=\sqrt[]{4^2+(-3)^2} \\ d=\sqrt[]{16+9} \\ d=\sqrt[]{25} \\ d=5 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20d%3D%5Csqrt%5B%5D%7B%283%2B1%29%5E2%2B%28-4%2B1%29%5E2%7D%20%5C%5C%20d%3D%5Csqrt%5B%5D%7B4%5E2%2B%28-3%29%5E2%7D%20%5C%5C%20d%3D%5Csqrt%5B%5D%7B16%2B9%7D%20%5C%5C%20d%3D%5Csqrt%5B%5D%7B25%7D%20%5C%5C%20d%3D5%20%5Cend%7Bgathered%7D)
the distance between the 2 points is 5 units
Answer:
2
Step-by-step explanation:
If two shapes are similar, this means the ratio of similar sides to each other are the same.
So, in the green shape, the long side length is 5 mm. In the purple shape, the long side length is 10 mm in length. The ratio is therefore 5 to 10, which can be simplified to 1 to 2 (which is basically saying that the side lengths of the purple shape are double the length of the sides of the green shape).
Using the same 1 to 2 ratio, you know that the short side length on the green shape is 1. The short side length on the purple shape (j) must therefore be double, which is 2.
