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Alenkasestr [34]
3 years ago
11

IS LITERALLY EVERYONE IGNORING MY QUESTIONS TODAY!!???

Mathematics
1 answer:
Likurg_2 [28]3 years ago
3 0
Nah i jus dont see em
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If (x) = -54 - 4 and g(x) = -3x - 2. find (f - g)(x).
Sholpan [36]

Set up the composite result function.

f

(

g

(

x

)

)

Evaluate

f

(

g

(

x

)

)

by substituting in the value of

g

into

f

.

4

(

x

−

2

)

Apply the distributive property.

f

(

x

−

2

)

=

4

x

+

4

⋅

−

2

Multiply

4

by

−

2

.

f

(

x

−

2

)

=

4

x -8

Step-by-step explanation:

4 0
4 years ago
Jay made a pizza he gave 1/4 of it to his mother 1/4 his father and one eight to his sister how much of the pizza is left
vesna_86 [32]
There is 3/8 of the pizza.
4 0
4 years ago
12. How many students scored at least 60 on the test?<br> a) 3<br> b) 4<br> c) 11<br> d) 7
Troyanec [42]
4
i don’t have an explanation
7 0
4 years ago
A farmer takes 1 week to fill 3 bins of squash. At this rate, how long will it take to fill 240 bins?
Oksanka [162]

Answer:

It will take 80 weeks to fill 240 bins full of squash.

Step-by-step explanation:

First we have to divide 3 by 240

3÷240=80

And Voila! That's our answer.

It will take 80 weeks to fill 240 bins full of squash.

Thanks! Mark me brainliest if this could help!

6 0
3 years ago
A lamina with constant density rho(x, y) = rho occupies the given region. Find the moments of inertia Ix and Iy and the radii of
jenyasd209 [6]

Answer:

Ix = Iy = \frac{ρπR^{4} }{16}

Radius of gyration x = y =  \frac{R}{4}

Step-by-step explanation:

Given: A lamina with constant density ρ(x, y) = ρ occupies the given region x2 + y2 ≤ a2 in the first quadrant.

Mass of disk = ρπR2

Moment of inertia about its perpendicular axis is \frac{MR^{2} }{2}. Moment of inertia of quarter disk about its perpendicular is \frac{MR^{2} }{8}.

Now using perpendicular axis theorem, Ix = Iy = \frac{MR^{2} }{16} = \frac{ρπR^{4} }{16}.

For Radius of gyration K, equate MK2 = MR2/16, K= R/4.

3 0
4 years ago
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