Answer:
A. 6
Step-by-step explanation:
f(x) = x² − 12x + 7
To complete the square, we first factor the leading coefficient to make it 1 (which it already is).
Then, we take half the second coefficient, square it, and then add to both sides. So (-12/2)² = (-6)² = 36.
f(x) + 36 = x² − 12x + 36 + 7
Then we factor the perfect square:
f(x) + 36 = (x − 6)² + 7
Then solve for f(x) by subtracting and simplifying:
f(x) = (x − 6)² + 7 − 36
f(x) = (x − 6)² − 29
So the value of a is 6.
You know that a perfect square trinomial is given by square of first term, twice the product of first and last terms and square of second term
So we have x^2 that is square of x, 2x that is twice the product of x*1, the second term shoulf be 1, that is square of 1
So your answer would be 1
If you try (x+1)^2 = x^2+2x+1
First, determine if the boundary line should be dotted or solid. In this case, it should be dotted because the symbol is less than not less than or equal to. This leaves you with options B or D. Now, to see if it should be shaded up or down, test it by substituting any point, let's say the origin (0,0), to see if that point is a solution to the equation. If it is, you shade that side of the graph, but if it's not, you shade the other side of the graph.
0 is less than (-3/4)(0) + 2
0 is less than 2.
Because 0 is actually less than 2, the statement is correct and you shade below the line
Answer: D
In 1 minute the copy machine copies = 24
That means
In 60 seconds the copy machine copies = 24
First we need to convert 5 minutes and 30 seconds to seconds
Then
5 minutes and 30 seconds = (5 * 60) + 30
= 300 + 30
= 330 seconds
So
In 330 seconds the copy machine will copy = (24/60) * 330
= 4 * 33
= 132
So in 5 minutes and 30 seconds the copy machine will copy 132 copies.
Answer:
The equations represent circles that result in the same graph.
Step-by-step explanation:
we have
Divide by -10 both sides
-----> equation A
This is the equation of a circle centered at origin with radius 
and
Divide by 5 both sides
-----> equation B
This is the equation of a circle centered at origin with radius
equation A and equation B are equal
therefore
The system has infinite solutions, because the equations represent circles that result in the same graph.
