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choli [55]
2 years ago
8

I need help in a and b ​

Mathematics
1 answer:
Deffense [45]2 years ago
3 0
A.24cm
B. 246.12 I'm is the answer!!!!!
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What factors of 48 are multiples of 4
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<span>4, 8, 12, 16, 24, 48</span>
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I need help. ASAP!<br> Divide.<br><br><br> (3b^3 – 10b^2 + 4) ÷ (3b – 1)
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3 years ago
An individual who has automobile insurance from a certain company is randomly selected. Let Y be the number of mov- ing violatio
olga2289 [7]

Answer:

a) E(Y) = \sum_{i=1}^n Y_i P(Y_i)

And replacing we got:

E(Y) =0*0.60 +1*0.25 +2*0.1 +3*0.05 = 0.60

b) E(Y^2) =0^2*0.60 +1^2*0.25 +2^2*0.1 +3^2*0.05 = 1.1

And then the expected value would be:

E(100Y^2) = 100*1.1= 110

Step-by-step explanation:

We assume the following distribution given:

Y       0       1        2        3

P(Y) 0.60 0.25  0.10  0.05

Part a

We can find the expected value with this formula:

E(Y) = \sum_{i=1}^n Y_i P(Y_i)

And replacing we got:

E(Y) =0*0.60 +1*0.25 +2*0.1 +3*0.05 = 0.60

Part b

If we want to find the expected value of 100 Y^2 we need to find the expected value of Y^2 and we have:

E(Y^2) = \sum_{i=1}^n Y^2_i P(Y_i)

And replacing we got:

E(Y^2) =0^2*0.60 +1^2*0.25 +2^2*0.1 +3^2*0.05 = 1.1

And then the expected value would be:

E(100Y^2) = 100*1.1= 110

4 0
3 years ago
There were several sunny days this year before my birthday. Since my birthday, there have been 171717 more sunny days. My birthd
Lesechka [4]

Answer:

66 sunny days before birthday

Step-by-step explanation:

Total sunny days after birthday = 17

Total sunny days in year = 83

Birthday was not sunny

Total sunny days before birthday = 83 -17

                                                       = 66 sunny days

Read more on Brainly.in - https://brainly.in/question/6937259#readmore

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3 years ago
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