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Rudiy27
3 years ago
15

I need help with this question. Pls give me an answer /steps and explanations.

Mathematics
2 answers:
Zina [86]3 years ago
4 0

Answer:

30s^5t^9u^{10}v^8

Step-by-step explanation:

We'll be using the following exponent property to solve this problem:

a^b\cdot a^c=(a)^{b+ c}

This will allow us to combine terms with the same variable.

In (5st^3u^9v^7)(6s^4t^6uv), we have four variables, s, t, u, and v.

Let's start with the s terms, 5s and 6s^4. The number in front of each term is called the coefficients, and can be multiplied directly. Remember that if there is no exponent written, it's the same thing as if there was an exponent of 1.

Therefore, combine using the exponent property I mentioned above:

5\cdot 6\cdot s^1\cdot s^4=30\cdot s^{1+4}=30s^5

Next, we'll move on to the t terms, t^3 and t^2.

Combine using the exponent property:

t^3\cdot t^6=t^{3+6}=t^9

Repeat for the u and v terms:

u^9\cdot u=u^{9+1}=u^{10}

v^7\cdot v=v^{7+1}=v^8

Finally, combine all the terms together:

\implies \boxed{30s^5t^9u^{10}v^8}

ASHA 777 [7]3 years ago
3 0

\bold{30s^{5}t^{9}u^{10}v^{8}}

Answer:

Express your answer using positive exponent.

\bold{(5st³u^{9}v^{7})(6s⁴t^{6}uv)}

adding power of common term and multiply constant term:

\bold{5*6*s^{1+4}*t^{3+6}*u^{9+1}*v^{7+1}}

\bold{30s^{5}*t^{9}*u^{10}*v^{8}}

\bold{30s^{5}t^{9}u^{10}v^{8}}

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Step-by-step explanation:Solve equations by clearing the Denominators Find the least common denominator of all the fractions in the equation. Multiply both sides of the equation by that LCD. This clears the fractions.

3 0
3 years ago
More help is appreciated:))
Lera25 [3.4K]

Step-by-step explanation:

You need to translate all the points to the right 3 and up 6

Therefore, you are going to use this formula:

(x,y) ⇾ (x + 3, y + 6)

This is the same format as the previous problem, if you have noticed.

Using this, plug in each coordinate, starting with  P (5, -1)

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(5, -1) ⇾ ( 8, 5 )

P^{1} = (8, 5)

Now point Q, (0, 8)

(0, 8) ⇾ (0 + 3, 8 + 6)

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And last but not least, the point R, (7, 5)

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R^{1} = (10, 11)

Therefore, P^{1} = (8, 5), Q^{1} = (3, 14), R^{1} = (10, 11) is your answer. This is the 4th option or D.

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6 0
3 years ago
Consider a series circuit consisting of a resistor of R ohms, an inductor of L henries, and variable voltage source of V(t) volt
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Answer:

I(t)=\frac{1}{3}(1-e^{-30t})

Step-by-step explanation:

We are given that

\frac{dI}{dt}+\frac{R}{L}I=\frac{V(t)}{L}

R=150 ohm

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I.F=e^{\int Pdt}=e^{\int 30 dt}=e^{30 t}

I(t)\times I.F=\int e^{30 t}\times 10 dt+C

I(t)\times e^{30 t}=\frac{10}{30}e^{30 t}+C

I(t)=\frac{1}{3}+Ce^{-30 t}

I(0)=0

Substitute t=0

0=\frac{1}{3}+C

C=-\frac{1}{3}

Substitute the values

I(t)=\frac{1}{3}-\frac{1}{3}e^{-30 t}

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Answer:

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Equating to zero;

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Hence the position of the ball when it is at its highest point is 121

Learn more on polynomial function here: brainly.com/question/2833285

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