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Rudiy27
3 years ago
15

I need help with this question. Pls give me an answer /steps and explanations.

Mathematics
2 answers:
Zina [86]3 years ago
4 0

Answer:

30s^5t^9u^{10}v^8

Step-by-step explanation:

We'll be using the following exponent property to solve this problem:

a^b\cdot a^c=(a)^{b+ c}

This will allow us to combine terms with the same variable.

In (5st^3u^9v^7)(6s^4t^6uv), we have four variables, s, t, u, and v.

Let's start with the s terms, 5s and 6s^4. The number in front of each term is called the coefficients, and can be multiplied directly. Remember that if there is no exponent written, it's the same thing as if there was an exponent of 1.

Therefore, combine using the exponent property I mentioned above:

5\cdot 6\cdot s^1\cdot s^4=30\cdot s^{1+4}=30s^5

Next, we'll move on to the t terms, t^3 and t^2.

Combine using the exponent property:

t^3\cdot t^6=t^{3+6}=t^9

Repeat for the u and v terms:

u^9\cdot u=u^{9+1}=u^{10}

v^7\cdot v=v^{7+1}=v^8

Finally, combine all the terms together:

\implies \boxed{30s^5t^9u^{10}v^8}

ASHA 777 [7]3 years ago
3 0

\bold{30s^{5}t^{9}u^{10}v^{8}}

Answer:

Express your answer using positive exponent.

\bold{(5st³u^{9}v^{7})(6s⁴t^{6}uv)}

adding power of common term and multiply constant term:

\bold{5*6*s^{1+4}*t^{3+6}*u^{9+1}*v^{7+1}}

\bold{30s^{5}*t^{9}*u^{10}*v^{8}}

\bold{30s^{5}t^{9}u^{10}v^{8}}

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<h3>How to determine the order of magnitude?</h3>

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