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lyudmila [28]
3 years ago
10

1.The Student Council is planning a dance. The cost to throw the dance will be $100 for decorations and

Mathematics
2 answers:
Kamila [148]3 years ago
3 0

Answer:

1a)  C = 600 + 5n

1b)  R = 6n

Step-by-step explanation:

Ugo [173]3 years ago
3 0

Answer:

1.

    a) $600+5n = C

    b) 6n = R

Step-by-step explanation:

For the cost to throw the event, we have to add $100+$500, the decorations and the DJ and then we have to add the variable for people times 5 since it is 5 per person. $100+500 = $600 and 5* n (the variable for people in the question)

We are adding the two terms so the final equation will be equal to:

600+5n

for b), we have to use the variable n for tickets times the constant 6 since it costs 6 dollars per person to enter, and that will be equal to the revenue the student council earns or R.

6*n = 6n

Now we have:

6n=R

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Lemur [1.5K]

Answer:

Cardiac output:F=0.055 L\s

Step-by-step explanation:

Given : The dye dilution method is used to measure cardiac output with 3 mg of dye.

To Find : Find the cardiac output.

Solution:

Formula of cardiac output:F=\frac{A}{\int\limits^T_0 {c(t)} \, dt} ---1

A = 3 mg

\int\limits^T_0 {c(t)} \, dt =\int\limits^{10}_0 {20te^{-0.06t}} \, dt

Do, integration by parts

[\int{20te^{-0.6t}} \, dt]^{10}_0=[20t\int{e^{-0.6t} \,dt}-\int[\frac{d[20t]}{dt}\int {e^{-0.6t} \, dt]dt]^{10}_0

[\int{20te^{-0.6t}} \, dt]^{10}_0=[\frac{-20te^{-0.6t}}{0.6}+\frac{20}{0.6}\int {e^{-0.6t} \,dt]^{10}_0

[\int{20te^{-0.6t}} \, dt]^{10}_0=[\frac{-20te^{-0.6t}}{0.6}+\frac{20e^{-0.6t}}{(0.6)^2}]^{10}_{0}

[\int{20te^{-0.6t}} \, dt]^{10}_0=[\frac{-200e^{-6}}{0.6}+\frac{20e^{-6}}{(0.6)^2}]+\frac{20}{(0.60^2}

[\int{20te^{-0.6t}} \, dt]^{10}_0=\frac{20(1-e^{-6}}{(0.6)^2}-\frac{200e^{-6}}{0.6}

[\int{20te^{-0.6t}} \, dt]^{10}_0\sim {54.49}

Substitute the value in 1

Cardiac output:F=\frac{3}{54.49}

Cardiac output:F=0.055 L\s

Hence Cardiac output:F=0.055 L\s

4 0
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Answer:

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Step-by-step explanation:

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-6 + 11 = 3c- 2c

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Answer:

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However, if you mean 5, 20, 80 it is a geometric sequence.

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