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Juli2301 [7.4K]
3 years ago
9

If £25 = 650 rubles, how many £ are in 780 rubles?

Mathematics
1 answer:
masya89 [10]3 years ago
3 0

Answer:

30

Step-by-step explanation:

25£ : 650 rubles

x£ : 780 rubles

25/x = 650/780

(cross multiply)

650x = 25×750

650x = 18 750

divide 18 750 by 650

which is = 30

thus x = 30

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Answer:

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Step-by-step explanation:

Answer in the attachment

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Natalija [7]

Select the second and fourth options.

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Please help!
Reika [66]

Answer:

(1,-5)

Step-by-step explanation:

The given system of inequalities are;

y\:

and

y\:

The point that is a solution will satisfy the two inequalities.

Checking for (1,-5)

-5\: and -5\:

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This point lies in the solution region.

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5\: and 5\:

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This point does not lie in the solution region.

Checking for (5,1)

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Select all the expressions that are equivalent to (2)^n+³
eimsori [14]

Answer:

The expressions which equivalent to  (2)^{n+3} are:

4(2)^{n+1}  ⇒ B

8(2)^{n} ⇒ C

Step-by-step explanation:

Let us revise some rules of exponent

  • a^{m} × a^{m}  = a^{m+n}
  • (a^{m})^{n} = a^{m*n}

Now let us find the equivalent expressions of  (2)^{n+3}

A.

∵ 4 = 2 × 2

∴ 4 =  2^{2}

∴  (4)^{n+2} =  (2^{2})^{n+2}

- By using the second rule above multiply 2 and (n + 2)

∵ 2(n + 2) = 2n + 4

∴  (4)^{n+2} =  (2)^{2n+4}  

B.

∵ 4 = 2 × 2

∴ 4 =  2²

∴  4(2)^{n+1} = 2² ×  (2)^{n+1}

- By using the first rule rule add the exponents of 2

∵ 2 + n + 1 = n + 3

∴   4(2)^{n+1} =  (2)^{n+3}

C.

∵ 8 = 2 × 2 × 2

∴ 8 =  2³

∴  8(2)^{n} = 2³ ×  (2)^{n}

- By using the first rule rule add the exponents of 2

∵ 3 + n = n + 3

∴  8(2)^{n} =  (2)^{n+3}

D.

∵ 16 = 2 × 2 × 2 × 2

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∵ 4 + n = n + 4

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E.

(2)^{2n+3} is in its simplest form

The expressions which equivalent to  (2)^{n+3} are:

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