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ehidna [41]
3 years ago
15

PLEASE HELP NOW!!

Mathematics
1 answer:
kow [346]3 years ago
7 0

Answer:

Point B is located where x is negative and y is positive.

Hope this helps!!

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The expression f(x) = 12(1.035)* models the monthly growth of membership in the new drama club at a school. According to the fun
olga nikolaevna [1]

Answer:

The monthly growth rate is 3.5%.

Step-by-step explanation:

The exponential growth function is given as follows:

y=a(1+r)^{x}

Here,

<em>y</em> = final value

<em>a</em> = initial value

<em>r</em> = growth rate

<em>x</em> = time taken

The provided expression for the monthly growth of membership in the new drama club at a school is:

f(x) = 12\cdot(1.035)^{x}

Comparing this function with the exponential growth function:

a(1+r)^{x}=12(1.035)^{x}\\\\a(1+r)^{x}=12(1+0.035)^{x}

Then value of <em>r</em> is 0.035 or 3.5%.

Thus, the monthly growth rate is 3.5%.

7 0
3 years ago
Select 3 ratios that are equivalent to 8:20​
guapka [62]

Answer:

4:10, 2:5 16:40

Step-by-step explanation:

just multiply or divide

5 0
3 years ago
How do I graph an equation?
Elanso [62]

Answer:

1. Locate the y-intercept on the graph and plot the point.

2. From this point, use the slope to find a second point and plot it.

3. Draw the line that connects the two points.

5 0
3 years ago
A number decreased by three square
Leto [7]
A number decreased by three square is: (where x is the number)

x - 3^2
8 0
3 years ago
FIND THE SUM OF 20 TERMS OF THE ARITHMETIC SERIES IN WHICH 3rd TERM IS 7 AND 7th TERM IS 2 MORE THAN THREE TIMES ITS 3rd TERM
algol13

Answer:

740

Step-by-step explanation:

The n th term of an arithmetic series is

a_{n} = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Given a₃ = 7 and a₇ = (3 × 7) + 2 = 21 + 2 = 23 , then

a₁ + 2d = 7 → (1)

a₁ + 6d = 23 → (2)

Subtract (1) from (2) term by term

4d = 16 ( divide both sides by 4 )

d = 4

Substitute d = 4 into (1)

a₁ + 2(4) = 7

a₁ + 8 = 7 ( subtract 8 from both sides )

a₁ = - 1

The sum to n terms of an arithmetic series is

S_{n} = \frac{n}{2} [ 2a₁ + (n - 1)d ] , thus

S_{20} = \frac{20}{2} [ (2 × - 1) + (19 × 4) ]

     = 10(- 2 + 76) = 10 × 74 = 740

8 0
3 years ago
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