Answer:
potential energy is answer
Explanation:
PV = nRT
P is pressure, V is volume, n is number of moles, R is the gas constant, T is temperature in K
(2.85 atm)(12.5 L) = (n)(.08206)(27 C + 273)
n = 1.45 moles x 35.45 grams / mol Cl2 = 51.3 grams
Answer: The charge on one electron is –1.6 x 10–19 coulomb.
Hope this helps!
25 drops of acid is required to neutralize the 50.0 ml of 0.010m of NaOH in the experiment.
The equation of the reaction is;
NaOH(aq) + HCl(aq) ---------> NaCl(aq) + H2O(l)
We can use the titration formula;
CAVA/CBVB = NA/NB
CA= concentration of acid
VA = volume of acid
CB = concentration of base
VB = volume of base
NA = number of moles of acid
NB = number of moles of base
CB = 0.010 M
VB = 50.0 ml
CA = 0.50 M
VA = ?
NA = 1
NB = 1
Substituting values;
CAVANB = CBVBNA
VA = 0.010 × 50.0 × 1/ 0.50 × 1
VA = 1 ml
Since the total volume of acid used is 1 ml and each drop contains 0.040 ml
The number of drops required is 1ml/0.040 ml = 25 drops
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