Answer:
T₂ = 242 K
Explanation:
According to general gas equation:
P₁V₁/T₁ = P₂V₂/T₂
Given data:
Initial volume = 125 mL
Initial pressure = 1.77 atm
Initial temperature = 213 °C (213 +273 = 486 K)
Final volume = 136 mL
Final pressure = 0.810 atm
Final temperature = ?
Solution:
P₁V₁/T₁ = P₂V₂/T₂
T₂ = P₂V₂T₁ / P₁V₁
T₂ = 0.810 atm × 136 mL × 486 K / 1.77 atm× 125 mL
T₂ = 53537.76 atm .mL. K / 221.25 atm . mL
T₂ = 242 K
The 3 particles are protons, neutrons, and electrons?
Answer:
Q = 31798.4J = 31.79kJ
Explanation:
Heat energy (Q) = ?
Mass (m) = 152g
T1 = 24°C
T2 = 74°C
Specific heat capacity of water (c) = 4.184J/g°C
Q = Mc∇T
Q = 152 * 4.184 * (74 - 24)
Q = 635.968 * 50
Q = 31798.4J
Q = 31.79kJ
Heat required is 31.79kJ
I believe it is C. I hope
Answer:
I Dont know sorry.........