The Depth of the Scientist before dropping is; 42.2 ft
<h3>How to calculate sea level elevation?</h3>
It is pertinent to note that sea level is usually considered zero level. Thus, one is either above the sea level (positive sign) or below the sea level.
Now, we are told that the scientist was already below the sea level before she dropped 24.9 ft.
Now, if after dropping 24.9 ft, she is now 66.7 ft below sea level, then it means that the depth she was at before dropping 24.9 ft is;
Depth before dropping 24.9 ft = 66.7 - 24.9
Depth before dropping = 42.2 ft
Read more about Sea level Elevation at; brainly.com/question/2092614
#SPJ1
Answer:
C. 0
Step-by-step explanation:
–4j^2 + 3j – 28 = 0
The discriminant is b^2-4ac if >0 we have 2 real solutions
=0 we have 1 real solutions
<0 we have 2 imaginary solutions
a = -4, b =3 c = -28
b^2 -4ac
(3)^2 - 4(-4)*(-28)
9 - 16(28)
9 -448
This will be negative so we have two imaginary solutions.
Therefore we have 0 real solutions
V = 4/3 (pi r times ^3) = formula for this knowing that you than
Combine volumes up (1ft times 3.14) + (2ft times 3.14) + (3ft times 3.14)
18.8 >. rounded to the nearest cubic foot of 19
