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kari74 [83]
3 years ago
6

Jen's has current assets of $2,200, cash of $400, and inventory of $1,300. The firm has accounts payable of $300, long-term debt

of $3,100, and accrued wages and taxes of $400. What is the quick ratio?
Mathematics
1 answer:
klasskru [66]3 years ago
6 0

Answer:

1.29

Step-by-step explanation:

Data provided in the question:

Current assets = $2,200

cash = $400

Inventory = $1,300

Accounts payable = $300

long-term debt = $3,100

Accrued wages and taxes = $400

Now,

Quick ratio = [ Current assets - Inventory ] ÷ [ Current liabilities  ]

also,

Current liabilities  = Accounts payable + Accrued wages and taxes

= $300 + $400

= $700

or

Quick ratio = [ $2,200 - $1,300 ] ÷ $700

or

Quick ratio = $900  ÷ $700

= 1.29

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If y varies inversely as x2 and y = 3 when x = 2, find the equation that connects x and y.
Bond [772]
<h3>Answer:  y = 12/(x^2)</h3>

============================================================

Explanation:

"y varies inversely as x^2" means y = k/(x^2) for some constant k.

Plug in (x,y) = (2,3) and solve for k

y = k/(x^2)

3 = k/(2^2)

3 = k/4

3*4 = k

12 = k

k = 12

The original equation updates to y = 12/(x^2)

As a check, plugging in x = 2 should lead to y = 3

y = 12/(x^2)

y = 12/(2^2)

y = 12/4

y = 3 ... we get the proper y value, so the answer is confirmed.

3 0
3 years ago
In 1995, there were 85 rabbits in Central Park. The population increased by 12% each year. How many rabbits
Goryan [66]

Answer:

918

Step-by-step explanation:

Given data

Initila population= 85

Rate = 12%

TIme= 21 years

Let us apply the compounding expression

A=P(1+r)^t

substitute

A= 85(1+0.12)^21

A=85(1.12)^21

A=85*10.80

A= 918

Hence the approximate Rabbit population will be 918

4 0
3 years ago
Prove that: [1 + 1/tan²theta] [1 + 1/cot² thata] = 1/(sin²theta - sin⁴theta]
Stels [109]

Step-by-step explanation:

<h3><u>Given :-</u></h3>

[1+(1/Tan²θ)] + [ 1+(1/Cot²θ)]

<h3><u>Required To Prove :-</u></h3>

[1+(1/Tan²θ)]+[1+(1/Cot²θ)] = 1/(Sin²θ-Sin⁴θ)

<h3><u>Proof :-</u></h3>

On taking LHS

[1+(1/Tan²θ)] + [ 1+(1/Cot²θ)]

We know that

Tan θ = 1/ Cot θ

and

Cot θ = 1/Tan θ

=> (1+Cot²θ)(1+Tan²θ)

=> (Cosec² θ) (Sec²θ)

Since Cosec²θ - Cot²θ = 1 and

Sec²θ - Tan²θ = 1

=> (1/Sin² θ)(1/Cos² θ)

Since , Cosec θ = 1/Sinθ

and Sec θ = 1/Cosθ

=> 1/(Sin²θ Cos²θ)

We know that Sin²θ+Cos²θ = 1

=> 1/[(Sin²θ)(1-Sin²θ)]

=> 1/(Sin²θ-Sin²θ Sin²θ)

=> 1/(Sin²θ - Sin⁴θ)

=> RHS

=> LHS = RHS

<u>Hence, Proved.</u>

<h3><u>Answer:-</u></h3>

[1+(1/Tan²θ)]+[1+(1/Cot²θ)] = 1/(Sin²θ-Sin⁴θ)

<h3><u>Used formulae:-</u></h3>

→ Tan θ = 1/ Cot θ

→ Cot θ = 1/Tan θ

→ Cosec θ = 1/Sinθ

→ Sec θ = 1/Cosθ

<h3><u>Used Identities :-</u></h3>

→ Cosec²θ - Cot²θ = 1

→ Sec²θ - Tan²θ = 1

→ Sin²θ+Cos²θ = 1

Hope this helps!!

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geniusboy [140]

Answer:

-1=7-8

Step-by-step explanation:

-1=7-8

-1=-1

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