Help me plzzzzz I will give you branliest

Can you help me please.

laila [671]

Answer:

69

Step-by-step explanation:

I just kept going up by 3 until the 20th term

5 0

3 years ago

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The expression(x 12) (y-13) (x-5) (y 4) is equivalent to xmxy. what is the value of n?

ANTONII [103]

Answer:

-9

Step-by-step explanation:

The applicable exponent rule is ...

a^b·a^c = a^(b+c)

___

For the y factor, ...

y^-13 · y^4 = y^(-13+4) = y^-9 . . . . . exponent of -9

3 0

4 years ago

a surveyor measures the distance to the two landmarks as shown in the diagram what is the distance d. between the landmarks

Inessa [10]

<h3>The distance between two landmarks is 123 meters</h3>

<em><u>Solution:</u></em>

We have to find the distance between two landmarks

<em><u>Use the law of cosines</u></em>

The third side of a triangle can be found when we know two sides and the angle between them

$c^2 = a^2 + b^2 - 2ab\ cos c$

Here, angle between 90 meters and 130 meters is 65 degrees

From figure,

a = 90

b = 130

c = d

Therefore,

$d^2 = 90^2 + 130^2 - 2(90)(130)\ cos 65\\\\d^2 = 8100 + 16900 - 23400\ cos\ 65\\\\d^2 = 25000 - 23400 \times 0.4226\\\\d^2 = 25000 - 9889.267\\\\d^2 = 15110.73\\\\d = 122.92\\\\d \approx 123$

Thus, the distance between two landmarks is 123 meters

8 0

4 years ago

If eight people sat at a round dinner table and each person had to shake everyone else’s hand once how many handshakes will take

Anna71 [15]

Each person shakes 7 hands, but once you count the handshake between A and B, you don't need to count the handshake between B and A. There are a total of 8*7/2 = 28 handshakes.

7 0

4 years ago

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Please answer a question the images.

Lyrx [107]

The distribution of the animals in the coral reef is an illustration of probability

<h3>The most likely animal</h3>

The distribution of the animals is given as:

Blue fish = 3

Yellow fish = 7

Sea turtle = 1

Eels = 3

The animal with the highest frequency is the most likely animal.

Hence, the Yellow fish is the most likely animal.

<h3>Which is more likely?</h3>

From the question, we have:

Blue fish = 3

Eels = 3

Both animals have the same frequency.

This means that Riley has equal chance of seeing a blue fish and an eel.

<h3>The probability of seeing an animal with fins</h3>

The animal with fins are:

Blue fish = 3

Yellow fish = 7

So, the probability is:

$p = \frac{3 + 7}{3 + 7 + 1 + 3}$

$p = \frac{10}{14}$

Simplify

$p = \frac 57$

Hence, the probability of seeing an animal with fins is 5/7

<h3>The least likely animal</h3>

The animal with the least frequency is:

Sea turtle = 1

So, the likelihood is:

$p = \frac 1{14}$

Hence, the sea turtle has the least likelihood of 1/14

<h3>Animals with equal likelihood</h3>

The Blue fish and the Eels have the same frequency of 3

This means that animals have equal likelihood

<h3>The probability of seeing each animal</h3>

We have:

Blue fish = 3

Yellow fish = 7

Sea turtle = 1

Eels = 3

Express as probability

Blue fish = 3/14

Yellow fish = 7/14

Sea turtle = 1/14

Eels = 3/14

Express the fractions as decimals

Blue fish = 0.214

Yellow fish = 0.500

Sea turtle = 0.071

Eels = 0.214

So, their likelihoods are:

Blue fish = Equally likely

Yellow fish = Certainly likely

Sea turtle = Unlikely

Eels = Equally likely