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ss7ja [257]
2 years ago
7

A rectangular skate park is 60 yards long and 50 yards wide

Mathematics
1 answer:
katrin2010 [14]2 years ago
6 0
Area: 3000 because multiply
perimeter:
2(60)+2(50)=120+100=220
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Round the following percentages to one decimal place.0.698%53.123%0.075%34.337%3.876%
balandron [24]

To round off a given number in decimals to one decimal place (1 dp), we simply take the figure right after the decimal and approximate the remaining after it. If the second number after the decimal is a significant number (5 and above) we make it 1 and add to the number right after the decimal. If its NOT a significant number, we simply disregard it. The solutions therefore are;

ANSWER:

\begin{gathered} \text{Rounded to one decimal place;} \\ (1)0.698\%\approx0.7 \\ (2)53.123\%\approx53.1 \\ (3)0.075\%\approx0.1 \end{gathered}

Notice how the number in (1) becomes 0.7, after taking the next number (which is 9) and adding it as 1 to the number after the decimal (which is 6). The same applies to the number in (3).

\begin{gathered} (4)34.337\%\approx34.3 \\ (5)3.876\%\approx3.9 \end{gathered}

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1 year ago
HELP!! HELP!! geometry
Colt1911 [192]

Answer:

Step-by-step explanation:

6 0
2 years ago
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A taxi cab driver charges a $2.00 initial fee and $1.75 for each mile.
umka21 [38]

1. She can travel 18 miles. Subtract 35 - 2 (initial fee) to have 33. divide 33 by 1.75 to get 18.85. To check how much her total would be, use inverse operations. 18.85 * 1.75 = 32.9875. 32.9875 + 2 = 34.9875. It is barely under $35 but still in her budget.

2. 20m * $1.75 = $35. $70 - $35 = $35. Yes, she can cover the fare. Samantha has more than needed. She can afford the taxi fare and still have money left for future use.

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2 years ago
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A used-car dealer sold one car at a profit of 25 percent of the dealer's purchase price for that car and sold another car at a l
Daniel [21]

Answer:

C. 1000 loss.

Step-by-step explanation:

Let x represent purchase price of each car.

We have been given that a used-car dealer sold one car at a profit of 25 percent of the dealer's purchase price for that car and sold another car at a loss of 20 percent of the dealer's purchase price for that car.

We can represent the car that dealer sold with 25% profit to find purchase price as:

x+0.25x=20,000

1.25x=20,000

\frac{1.25x}{1.25}=\frac{20,000}{1.25}

x=16,000

Therefore, the purchase price of 1st car was $16,000.

We can represent the car that dealer sold with 20% loss to find purchase price as:

x-0.20x=20,000

0.80x=20,000

\frac{0.80x}{0.80}=\frac{20,000}{0.80}

x=25,000

Therefore, the purchase price of 2nd car was $25,000.

The total purchase price of both cars would be 16,000+25,000=41,000

The total sale price of both cars 20,000+20,000=40,000.

We can see that the sale price of both car is less than purchase price by $1000, so the dealer got a loss of $1000.

Therefore, the dealer's total loss, in dollars, for the two transactions combined was 1000 and option C is the correct choice.

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3 years ago
It is commonly said that 10 of people are left-handed, but Lilianna suspected that a higher proportion of art students at her un
Vladimir [108]

Answer:

.08

Step-by-step explanation:

khan

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3 years ago
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