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FrozenT [24]
4 years ago
5

Geothermal energy helps to

Chemistry
1 answer:
disa [49]4 years ago
4 0

Answer:A

Explanation:

You might be interested in
1. How many metals, nonmetals and metalloids are there in the periodic table?
sweet-ann [11.9K]

Answer:

There are 110 elements known to us, out of which 92 are naturally occurring, while the rest have been prepared artificially. Elements are further classified into metals, non-metals, and metalloids..

Explanation:

Hope it helps you..

Y-your welcome in advance..

(;ŏ﹏ŏ)(ㆁωㆁ)

8 0
3 years ago
I want to see how the temperature of water affects the speed of rusting. What is the Independent Variable
Butoxors [25]
I want to see how the temperature of water affects the speed of rusting. What is the Independent Variable?

The Independent Variable is the temperature of water.
7 0
3 years ago
How to solve #2, not sure if my work is correct
erica [24]
Go through your work carefully i see a mistake in number 2
5 0
3 years ago
Extracted from olives, canola, and corn are plant lipids and are liquid at room temperature.
Aleks [24]

Answer:

<em>OILS</em>

Explanation:

Oils are viscous liquids at room temperature, with high carbon and hydrogen content. Vegetable oils in this case are triglycerides extracted from plants seeds or fruit.

So we'd have olive oils, canola oils and corn oils.

I hope this explanation is clear and simple.

5 0
3 years ago
How much energy (joules) is needed to heat 250 grams of water from 22 °C to 99 °C?
iris [78.8K]

Answer:

\boxed {\boxed {\sf 80, 465 \ Joules}}

Explanation:

We can use the specific heat formula, which is:

q=mc \Delta T

Where <em>q</em> is the energy, <em>m</em> is the mass, <em>c</em> is the specific heat capacity, and ΔT is  the change in temperature.

We know the mass is 250 grams. The specific heat capacity of water is 4.18 joules per gram degree Celsius. Let's find the change in temperature.

  • ΔT = final temperature - initial temperature
  • ΔT= 99°C- 22°
  • ΔT= 77°C

Now we know all the values:

  • m= 250 g
  • c= 4.18 J/ g °C
  • ΔT= 77°C

Substitute the known values into the formula.

q=(250 \ g) (4.18 \ J/g \textdegree C)(77 \ \textdegree C)

Multiply the first 2 numbers together. The grams will cancel out.

q=1045 \ J/ \textdegree C (77 \textdegree C)

Multiply again. This time the degrees Celsius will cancel out.

q=80465 \ J

The energy needed is <u>80, 465 Joules.</u>

3 0
3 years ago
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