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GenaCL600 [577]
3 years ago
11

100 PONTS AND BRAINLIEST What is the maximum number of formula units of NaCl in one mole?"

Chemistry
2 answers:
natulia [17]3 years ago
5 0

Answer:

The meaning and usefulness of the mole Page 2 2 • One mole of NaCl contains 6.022 x 1023 NaCl formula units. Use the mole quantity to count formulas by weighing them.

Ilia_Sergeevich [38]3 years ago
4 0

Answer:

The meaning and usefulness of the mole Page 2 2 • One mole of NaCl contains 6.022 x 1023 NaCl formula units. Use the mole quantity to count formulas by weighing them.

Explanation:

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Magnesium metal is added to excess acid to generate hydrogen gas, which is collected over water at 25.0°C (vapour pressure of wa
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Answer:

Explanation:

PV / RT =  n , n is number of moles

Total pressure  = 96400 Pa

vapour pressure = 23.8 mm of Hg

= .0238 x 13.6 x 10³ x 10 Pa = 3236.8 Pa

Pressure of hydrogen gas P = 96400 - 3236.8

= 93163.2 Pa

n = 93163.2 x .0251 / 8.31 x 298

= .944 moles of hydrogen gas is produced

moles of magnesium reacted = .944

grams of magnesium reacted = .944 x 24 = 22.66 grams .

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Consider this question: What is the molarity of KMnO4 in a solution of 0.0908 g of KMnO4 in 0.500 L of solution?
natita [175]

Answer:

0.0011 M.

Explanation:

Molarity of a substance , is the number of moles present in a liter of solution .

M = n / V

M = molarity

V = volume of solution in liter ,

n = moles of solute ,

Moles is denoted by given mass divided by the molecular mass ,

Hence ,

n = w / m

n = moles ,

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m = molecular mass .

From the question ,

w = given mass of KMnO₄ = 0.0908 g

and ,

V = 0.500 L

Since ,

we know ,

m = Molecular mass of   KMnO₄ =  158 g/mol

using , the above formula to calculate the moles ,

n = w / m = 0.0908 g / 158 g/mol = 0.00057 mol

now , calculating the molarity as ,

M = n / V =  0.00057 mol / 0.500 L = 0.0011 M.

6 0
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