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Lorico [155]
3 years ago
6

On a coordinate plane, rhombus W X Y Z is shown. Point W is at (7, 2), point X is at (5, negative 1), point Y is at (3, 2), and

point Z is at (5, 5).
What is the perimeter of rhombus WXYZ?
Mathematics
1 answer:
valentinak56 [21]3 years ago
4 0

the answer is 4,13 of the perimeter

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Compute​ P(x) using the binomial probability formula. Then determine whether the normal distribution can be used to estimate thi
stich3 [128]

Answer:

The answers to the questions are;

A) P(X) where x = 12 is equal to 3.55 ×10⁻²

B) P(x) using the normal distribution is given by the probability distribution function and is equal to 3.453 ×10⁻²

C) The calculated probabilities of P(x=12) using the binomial probability formula and the probability distribution function differ by 9.7×10⁻⁴

D) The normal distribution be used to approximate this probability because     a. because np(1-p) %u2265 ⇒ np(1-p) ≥ 10

E) c. the value of fi represents the expected proportion of observation less than or equal to the ith data value.

Step-by-step explanation:

To solve the question, we note that

n = 58

p = 0.3

x = 12

Here we have n·p = 17.4 and n·q = 40.6 both ≥ 5 that is the normal distribution can be used to estimate the probability

A) We are to use the binomial probability formula to find P(X)

Where x = 12, we have P(12) = ₅₈C₁₂×0.3¹²×0.7⁴⁶

= 891794789340×0.000000531441×7.49×10⁻⁸ = 3.55 ×10⁻²

B) Using the standard distribution table we have

the z score for x = 12 given as z = \frac{x-\mu}{\sigma} = -1.55

From the normal distribution table, we have the probability that value is below 12 = .06057 while the normal probability distribution function which gives the probability of a number being 12 is given by

\frac{1}{\sigma\sqrt{2 \pi } } e^{\frac{-(x-\mu)^2}{2\sigma^2} }

where:

σ = Standard deviation = \sqrt{npq} = \sqrt{np(1-p)} = \sqrt{58*0.3*(1-0.3)} = 3.48999

μ = Sample mean = n·p = 58×0.3 =17.4

Therefore the probability density function is \frac{1}{3.49\sqrt{2 \pi } } e^{\frac{-(12-17.4)^2}{2*3.49^2} } = 3.453*10^{-2}

C)  The probabilities differ by 3.55 ×10⁻² -  3.453 ×10⁻² =  9.7×10⁻⁴

D) The normal distribution be used to approximate this probability because     n·p and n·p·(n-p) ≥ 5

E)   f_i represents the area under the curve towards left of the ith data observed in a normally distributed population.

Therefore, the value of fi represents the expected proportion of observation less than or equal to the ith data value  

5 0
3 years ago
Tonisha has a lemonade stand. She has 34$ in expenses and wants to make at least 80$per day.
lukranit [14]

Answer:

is there anything else to the question?

Step-by-step explanation:

8 0
3 years ago
Did i get number 2 right or wrong if i got it wrong tell me the answer
weeeeeb [17]

Answer:

Wouldn't it be 1/3 ??

because there is one column filled and there are three columns so that would make it 1/3 out of 3

4 0
3 years ago
Each student receives one of 4 calculator models and one of 3 types of ruler. How many possible outcomes are there if a student
Tanzania [10]

Answer:

24 possible outcomes

Step-by-step explanation:

Combination has to do with selection. For example, if r object is selected from a pool of n objects, the number if possible ways can be expressed according to the combination formula:

nCr = n!/(n-r)!r!

Applying this in question, if each student receives one of 4 calculator models and one of 3 types of ruler, the number of ways this can be done is:

4C1 × 3C1

4C1 = 4!/(4-1)!1! {If a student gets one calculator)

4C1 = 4×3×2/3×2

4C1 = 4ways

3C1 = 3!/(3-2)!1! {If a student gets a ruler}

3C1 = 3×2/1

3C1 = 6ways

Total number of possible outcomes if a student gets one ruler and one calculator will be 4×6 = 24ways

5 0
3 years ago
PLEASE HELP!!!!
aivan3 [116]

Answer:

d

Step-by-step explanation:

=1000

10^3 is 1000

3 0
3 years ago
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