Here's an example
Y=5x + 10
if x is equal to 5 you would make it
Y=5(5)+10.
basically, just replace the x with what it's equal to.
Answer is 1 1/12
3(1/4 + 1/2^2)+ (2x1/12)
3/4+1/4+2/12 (you get to this part by distributing 3 throughout the parentheses)
9/12+3/12+2/12= 1 1/12 hope this helps
Answer:
.
Step-by-step explanation:
Given the statement
If , then E and F are mutually exclusive events.
If two events are mutually exclusive, they have no elements in common. Thus, P(E∩F)=0.
Therefore, the statement is always true as P(E∩F)=0
For mutually exclusive events:
.
Answer: 1/70
Step-by-step explanation:
This is a question that can also be interpreted as what is the probability of having the first number of a phone number to be 8 and the last number of the phone number to also be 8. This answer gives the fraction of the phone numbers that starts with 8 and end with 8.
Since three numbers (0,1,2) cannot start a phone number and we are left to pick from 7 numbers,
then the probability of figure "8" starting phone number = 1/7
Since all 10 numbers can possibly end a phone number,
then the probability of having figure "8" as the last digit of a phone number = 1/10
Hence probability of having "8" as the first and last digit of a phone number = fraction of total telephone numbers that begin with digit 8 and end with digit 8 = 1/7 × 1/10 = 1/70.