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il63 [147K]
3 years ago
14

The density of silver is 10.49 g/mL. If a sample of pure silver has a volume of 12.993 mL, what is the mass of the silver?

Chemistry
1 answer:
r-ruslan [8.4K]3 years ago
4 0

Answer:

see the pic for more detail

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If the pressure on a 1.04 L sample of gas is doubled at constant temperature, please compute the new volume of gas: __
natulia [17]

Answer:

0.52 L.

Explanation:

Let P be the initial pressure.

From the question given above, the following data were obtained:

Initial pressure (P1) = P

Initial volume (V1) = 1.04 L

Final pressure (P2) = double the initial pressure = 2P

Final volume (V2) =?

The new volume (V2) of the gas can be obtained by using the the Boyle's law equation as shown below:

P1V1 = P2V2

P × 1.04 = 2P × V2

1.04P = 2P × V2

Divide both side by 2P

V2 = 1.04P /2P

V2 = 0.52 L

Thus, the new volume of the gas is 0.52 L.

6 0
3 years ago
A gas occupies a volume at 34.2 mL at a temperature of 15.0 C and a pressure of 800.0 torr. What will be the volume of this gas
Grace [21]
The answer is 34.1 mL.
Solution:
Assuming ideal behavior of gases, we can use the universal gas law equation
     P1V1/T1 = P2V2/T2
The terms with subscripts of one represent the given initial values while for terms with subscripts of two represent the standard states which is the final condition.
At STP, P2 is 760.0torr and T2 is 0°C or 273.15K. Substituting the values to the ideal gas expression, we can now calculate for the volume V2 of the gas at STP:
     (800.0torr * 34.2mL) / 288.15K = (760.0torr * V2) / 273.15K
     V2 = (800.0torr * 34.2mL * 273.15K) / (288.15K * 760.0torr)
     V2 = 34.1 mL
3 0
3 years ago
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What would be the IUPAC name of PoTs2
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Answer:

6-methylhept-1-en-3-one

Explanation:

6 0
3 years ago
How many valence electrons are in a stable ion of a period 4 metal?
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What kind of metal is it
8 0
3 years ago
Capsaicin, the compound that gives the hot taste to chili peppers, has the formula C18H27NO3. Its molar mass is 305.42 g/mol. Ca
stellarik [79]
Molar mass = 305.42 g/mol

C = ( 12 x 18 / 305.42 ) x 100 => 70.72 % of C

H = ( 1 x 27 / 305.42 ) x 100 => 8.84 % of H

N = ( 14 x 1 / 305.42 ) x 100 => 4.58 % of N

O = ( 16 x 3 / 305.42) x 100 => 15.71% of O

hope this helps!
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3 years ago
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