All categories

2 years ago

Identify the type of reaction in the chemical reaction below:

Chemistry

1 answer:

Morgarella [4.7K]2 years ago

6 0

Complete question is;

Identify the type of reaction in the chemical reaction below:

2P205 ➡️ 4P + 502

single replacement

synthesis

decomposition

combustion

double replacement

Answer:

Decomposition

Explanation:

We. An see in the question that the compound 2P205 is broken down into simpler substances which are phosphorus (P) and oxygen (O).

Now, this is a decomposition reaction because a decomposition reaction is one in which a compound is broken down into simpler substances

You might be interested in

Anil accidentally swallows a substance that activates the complement cascade in the absence of bound antibodies. this substance

ale4655 [162]

Answer:

This substance would cause cause an extensive cellular damage to Anil.

5 0

2 years ago

Which of the elements must be available in water for the metamorphosis of tadpoles?

Grace [21]

The element iodine (I) is important for the fast and hastened metamorphosis of frog-tadpoles. As amphibians, the tadpoles can live in water and land but when they are born they are iodine-deficient. Tadpoles that do not receive ample amount of iodine become tadpoles until the end of their days.

8 0

3 years ago

Find the quantinum numbers n,m,l,s for the last of potassium layer pleasee help explain correctly all

Fantom [35]

Answer:

Quantum numbers of the outermost electron in potassium:

$n = 4$ .
$l = 1$ .
$m_l = 0$ .
Either $m_s = 1/2$ .

Explanation:

Refer to the electron configuration of a potassium atom. The outermost electron in a ground-state potassium atom is in the $4s$ orbital (fourth $s$ orbital.)

The quantum number $n$ (the principal quantum number) specifies the main energy shell of an electron. This electron is in the fourth main energy shell (as seen in the number four in the orbital.) Hence, $n = 4$ for this electron.

The quantum number $l$ (the angular momentum quantum number) specifies the shape ( $s$ , $p$ , $d$ , etc.) of an electron. $l = 1$ for $s\!$ orbitals (such as the one that contains this electron.

Quantum numbers $n$ and $l$ specify the shape of an orbital. On the other hand, the magnetic quantum number $m_l$ specifies the orientation of these orbitals in space.

However, $s$ orbitals are spherical. Regardless of the value of $n$ , the only possible $m_l$ value for electrons in $s\!$ orbitals is $m_l = 0$ .

The spin quantum number $m_s$ distinguishes between the two electrons in an orbital. The two possible values of $m_s \!$ are $(+1/2)$ and $(-1/2)$ . Typically, the first electron in an orbital is assigned an upward ( $\uparrow$ ) spin, which corresponds to $m_s = (+1/2)$ .