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sukhopar [10]
3 years ago
6

What is the easiest way to explain molecular compounds and covalent bonds also adding information about valance electrons?

Chemistry
1 answer:
wlad13 [49]3 years ago
5 0

Answer:

Molecular compounds consist of two or more nonmetals. The nonmetals that make up a molecular compound are held together by covalent/molecular bonds. Covalent bonds is known as the "sharing" of valence electrons between two or more chemical species. Valence electrons are shared so that the atoms of the compound can become stable, much like how ionic bonds transfer valence electrons between atoms to achieve stability.

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diphenyl compound does not follow huckle rule for an organic compound to be aromatic, yet it is aromatic. how? ...?
Minchanka [31]
No, it doesn't. According to huckle rule it must have 14 \pi<span> electrons to be aromatic but it has only 12 pi electrons. then how does it follow the rule?

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
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4 years ago
21&lt;2x+3 help fast please ​
kolezko [41]

Answer:

Explanation:

x in (-oo:+oo)

2 < (1/2)*x-3 // - (1/2)*x-3

2-((1/2)*x)+3 < 0

(-1/2)*x+2+3 < 0

5-1/2*x < 0 // - 5

-1/2*x < -5 // : -1/2

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x in (10:+oo)

(10:+oo)

7 0
3 years ago
Read 2 more answers
Consider the following reaction: CO(g)+2H2(g)⇌CH3OH(g) Kp=2.26×104 at 25 ∘C. Calculate ΔGrxn for the reaction at 25 ∘C under eac
nlexa [21]

Answer : The value of \Delta G_{rxn} is, 8.867kJ/mole

Explanation :

The formula used for \Delta G_{rxn} is:

\Delta G_{rxn}=\Delta G^o+RT\ln Q   ............(1)

where,

\Delta G_{rxn} = Gibbs free energy for the reaction

\Delta G_^o =  standard Gibbs free energy

R = gas constant = 8.314 J/mole.K

T = temperature = 25^oC=273+25=298K

Q = reaction quotient

First we have to calculate the \Delta G_^o.

Formula used :

\Delta G^o=-RT\times \ln K_p

Now put all the given values in this formula, we get:

\Delta G^o=-(8.314J/mole.K)\times (298K)\times \ln (2.26\times 10^{4})

\Delta G^o=-24839.406J/mole=-24.83\times 10^3J/mole=-24.83kJ/mole

Now we have to calculate the value of 'Q'.

The given balanced chemical reaction is,

CO(g)+2H_2(g)\rightarrow CH_3OH(g)

The expression for reaction quotient will be :

Q=\frac{(p_{CH_3OH})}{(p_{CO})\times (p_{H_2})^2}

In this expression, only gaseous or aqueous states are includes and pure liquid or solid states are omitted.

Now put all the given values in this expression, we get

Q=\frac{(1.4)}{(1.2\times 10^{-2})\times (1.2\times 10^{-2})^2}

Q=8.1\times 10^{5}

Now we have to calculate the value of \Delta G_{rxn} by using relation (1).

\Delta G_{rxn}=\Delta G^o+RT\ln Q

Now put all the given values in this formula, we get:

\Delta G_{rxn}=-24.83kJ/mole+(8.314\times 10^{-3}kJ/mole.K)\times (298K)\ln (8.1\times 10^{5})

\Delta G_{rxn}=8.867\times 10^3J/mole=8.867kJ/mole

Therefore, the value of \Delta G_{rxn} is, 8.867kJ/mole

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3 years ago
Joe is lifting boxes to load a trailer. To follow proper lifting procedures, Joe should:
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<span>oe is lifting boxes to load a trailer. To follow proper lifting procedures, Joe should:</span>
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4 years ago
I need help with this answer
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