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Sergio039 [100]
3 years ago
13

Answerr fasttt pleaseee lets see who can answer

Chemistry
1 answer:
bazaltina [42]3 years ago
6 0
B it is the most reasonable answer <span />
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(a) In a gaseous sample of oxygen atoms and diatomic oxygen in equilibrium at 298K andunder a pressure of 1atm, what fraction of
ZanzabumX [31]

Answer:

Explanation:see below as shown from pics

7 0
3 years ago
can anyone explain to me how to balance a chemical equation? im having trouble in understanding how i keep getting it wrong.
Virty [35]
For example we are going to use this unbalanced chemical reaction:
H₂ + O₂ → H₂O.
First, calculate number of atoms (hydrogens and oxygens) on left and right. There is two oxygen and two hydrogen on left and two hydrogen and one oxygen on right.
You can not change molecular formula of compound, only you can put coefficient in fron of compound to balance reaction.
Put 2 in front water to balance oxygen (now you have two oxygens on left and right). But now you have four hydrogens on right, so you must put 2 in fron hydrogen on the left.
2H₂ + O₂ → 2H₂O.
6 0
3 years ago
Read 2 more answers
A transverse wave that has electrical and
Semenov [28]
Electromagnetic energy would be your answer :)
6 0
2 years ago
Which of the following measurements are listed in the proper mathematical relationship?(Select all that apply)
Igoryamba

The measurements which are listed in the proper mathematical relationship include:

  • PV=k
  • V/T=k
  • PV/T = k

<h3>What is a Constant?</h3>

This is used in mathematical expressions and has a constant value which doesn't change in expression.

Options A,B and C have the appropriate constants as pressure is usually multiplied by volume.

Read more about Constant here brainly.com/question/15989275

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8 0
2 years ago
If the temperature of a gas confined to such a cylinder is raised from 287°C to 587°C, what is the ratio of the initial volume t
jenyasd209 [6]

Answer:

1 : 2

Explanation:

From the question given, we obtained the following information:

T1 = 287°C = 287 +273 = 560K

T1 = 587°C = 587 +273 =860K

V1 = V

V2 =?

V1 /T1 = V2 /T2

V/560 = V2/860

Cross multiply

V2 x 560 = 860 x V

Divide both side by 560

V2 = (860 x V) / 560

V2 = 1.54V = 2V

The ratio of initial to final volume =

V1 : V2

= V : 2V

= 1 : 2

8 0
3 years ago
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