Answer:
false it's 24 hours long.
Answer:
158 L.
Explanation:
What is given?
Pressure (P) = 1 atm.
Temperature (T) = 112 °C + 273 = 385 K.
Mass of methane CH4 (g) = 80.0 g.
Molar mass of methane CH4 = 16 g/mol.
R constant = 0.0821 L*atm/mol*K.
What do we need? Volume (V).
Step-by-step solution:
To solve this problem, we have to use ideal gas law: the ideal gas law is a single equation which relates the pressure, volume, temperature, and number of moles of an ideal gas. The formula is:

Where P is pressure, V is volume, n is the number of moles, R is the constant and T is temperature.
So, let's find the number of moles that are in 80.0 g of methane using its molar mass. This conversion is:

So, in this case, n=5.
Now, let's solve for 'V' and replace the given values in the ideal gas law equation:

The volume would be 158 L.
Answer:
See explanations
Explanation:
a. Molarity = moles/Volume in Liters = 5moles/2Liters = 2.5M in NaCl
b. Freezing Pt Depression
1. Sprinkling salt on icy surfaces
2. Using antifreeze in automobile cooling systems
3. <em>Not an application
</em>
4. Using salt to make ice cream
c. pOH = -log[OHˉ] = -log(1x10ˉ¹⁰) = -(-10) = 10 => pH = 14 – pOH = 14 – 10 = 4
d. H₂O + NH₃ => NH₄⁺ + OHˉ => Bronsted Acid is H₂O (proton donor)
Answer:
<u>CH</u>
Explanation:
Molecular formula of propene : <u>C₃H₆</u>
Take the HCF of carbon and hydrogen atoms :
Then, we can write the formula as :
- 3CH
- This means there are 3 moles present
Empirical Formula :
- Molecular Formula / No. of moles
- C₃H₆ / 3
- <u>CH</u>
<u></u>
The empirical formula of propene is <u>CH</u>
Answer: The standard entropy of vaporization of ethanol is 0.275 J/K
Explanation:

Using Gibbs Helmholtz equation:

For a phase change, the reaction remains in equilibrium, thus 

Given: Temperature = 285.0 K

Putting the values in the equation:


Thus the standard entropy of vaporization of ethanol is 0.275 J/K