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4 years ago

For the homogeneous solution, consisting of kcl and h2o, indicate the type of forces that are involved.

1 answer:

4 0

<span>The pairs of substances I would expect to form homogeneous solutions when combined will form a homogeneous because both are polar and form dispersion forces, dipole-dipole and hydrogen bonding between the water molecules and ion-dipole forces between the K+ and Cl- ions and the water molecules.</span>

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Complete and balance the reaction in acidic solution. equation: ZnS + NO_{3}^{-} -> Zn^{2+} + S + NO ZnS+NO−3⟶Zn2++S+NO Which

kotykmax [81]

Answer:

Balanced reaction: $3ZnS+2NO_{3}^{-}+8H^{+}\rightarrow 3Zn^{2+}+3S+2NO+4H_{2}O$

S is oxidized and N is reduced.

$NO_{3}^{-}$ is the oxidizing agent and ZnS is the reducing agent.

Explanation:

Reaction: $ZnS+NO_{3}^{-}\rightarrow Zn^{2+}+S+NO$

$\Rightarrow$ Oxidation: $ZnS\rightarrow Zn^{2+}+S$

Balance charge: $ZnS-2e^{-}\rightarrow Zn^{2+}+S$ ...............(1)

$\Rightarrow$ Reduction: $NO_{3}^{-}\rightarrow NO$

Balance H and O in acidic medium : $NO_{3}^{-}+4H^{+}\rightarrow NO+2H_{2}O$

Balance charge: $NO_{3}^{-}+4H^{+}+3e^{-}\rightarrow NO+2H_{2}O$ ...............(2)

[ $3\times$ Equation-(1)] + [ $2\times$ Equation-(2)]:

$3ZnS+2NO_{3}^{-}+8H^{+}\rightarrow 3Zn^{2+}+3S+2NO+4H_{2}O$

Oxidation number of S increases from (-2) to (0) for the conversion of ZnS to S. Therefore S is oxidized.

Oxidation number of N decreases from (+5) to (+2) for the conversion of $NO_{3}^{-}$ to NO. Therefore N is reduced.

$NO_{3}^{-}$ consumes electron from ZnS. Therefore $NO_{3}^{-}$ is the oxidizing agent and ZnS is the reducing agent.

7 0

4 years ago

How are sublimation in evaporation similar

diamong [38]

Evaporation is when a liquid turns into a gas, while sublimation is when a solid turns into a gas. Both involve absorbing energy to break apart the bonds of the substance. On the other hand, an example of sublimation is dry ice.

3 0

3 years ago

Read 2 more answers

A student was provided with a solid sample made up of a mixture of components. Prior to separation, the student measured 2.895 g

Shtirlitz [24]

Answer:

Component 1, since it has the greatest mass.

Explanation:

Hello,

In this case, considering that the by-mass percent of a substance is computed:

$\% m/m_i=\frac{m_i}{m_{mixture}}*100\%$

In such a way, given the form of the equation one could infer that the higher the mass of the i component, the higher its by-mass percent, it means that the component with the greatest mass will have the highest by-mass percent for the mixture. In such a way, since the component 1 was found to have a mass of 1.12 g, it will have the highest by-mass percent.

Best regards.

7 0

3 years ago

PLEASE NO FAKE ANSWERS!! Chemistry!!! Please will give brainliest !! Show work

Drupady [299]

When 1 mole of Zn and 2 mole of O₂ reacts togethor, It will produce 1 mole of ZnO as O₂ is excess reagent and Zn will act as Limiting reagent and thus it limits the amount of product formed.

<h3>What is Limiting reagent ?</h3>

Limiting reagents are the substances that are completely consumed first in a chemical reaction.

Given ;

Amopunt of Zn : 1 mole
Amount of O₂ : 2 mole

Given equation ;

2Zn + O₂ --> 2ZnO

As according to given chemical equation,

2 moles Zn of reacts with 1 mole of O₂ to produce 2 moles of ZnO.

Therefore,

1 mole of Zn will require 0.5 mole of O₂.

But,

the given amount of O₂ is 2 mole which is excess

Hence,

Zn here will act as the Limiting reagent, According to which the amount of product formed will be decided.

Therefore,

If 2 mole Zn produces : 2 moles of ZnO (According to given balanced equation)

Thus,

1 mole of Zn will produce = 2/2 x 1

= 1 mole of ZnO

Hence, When 1 mole of Zn and 2 mole of O₂ reacts togethor, It will produce 1 mole of ZnO as O₂ is excess reagent and Zn will act as Limiting reagent and thus it limits the amount of product formed.

Learn more about Limiting reagent here ;

brainly.com/question/11848702

#SPJ1

3 0

2 years ago

1. Calculate the molarity of a sugar solution if 4 liters of the solution contains 8 moles of sugar

klio [65]

Answer:

The molarity of a sugar solution is 2 M.

Explanation:

Molarity is a concentration measure that expresses the moles of solute per liter of solution. In this case it is calculated with the simple rule of three:

4 L of solution--------8 moles of sugar

1 L of solution ------x= (1 L of solution x 8 moles of sugar)/4 L of solution

x=2 moles of sugar---> <em>The solution is 2M</em>

8 0

3 years ago