What is the product of the reaction below?

The solid product from reaction of sulfuric acid with sucrose is?

Mama L [17]

$\huge{\mathbb{\tt {QUESTION:}}}$

The solid product from reaction of sulfuric acid with sucrose is?

$\huge{\mathbb{\tt {ANSWER:}}}$

Concentrated <u>sulfuric acid</u> is added to sucrose forming carbon, steam and <u>sulfur</u> dioxide.

<h3>RELATED TO THE QUESTION </h3>

$\huge{\mathbb{\tt {What \: is \: solid?:}}}$

<u>Solid is one of the four fundamental states of matter</u>. The molecules in a solid are closely packed together and contain the least amount of kinetic energy.
<u>A solid is characterized by structural rigidity and resistance to a force applied to the surface</u>.

$\huge{\mathbb{\tt {What \: is \: sulfur \: acid?}}}$

<u>Sulfuric acid or sulphuric acid, also known as oil of vitriol, is a mineral acid composed of the elements sulfur, oxygen and hydrogen</u>, with molecular formula H₂SO₄. It is a colorless, odorless and viscous liquid that is miscible with water at all concentrations.

$\huge{\mathbb{\tt{What \: is \: sucrose?}}}$

<u>Sucrose is common sugar. It is a disaccharide</u>, a molecule composed of two monosaccharides: glucose and fructose. Sucrose is produced naturally in plants, from which table sugar is refined. It has the molecular formula C₁₂H₂₂O₁₁.

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<h3>→XxKim02xX</h3>

6 0

2 years ago

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trasher [3.6K]

Protons are positive

3 0

3 years ago

Calculate ΔH for the reaction: C(graphite) + 2H 2(g) + 1/2 O 2(g) => CH 3OH(l) Using the following information: C(graphite) +

Alika [10]

Answer:

$\Delta H$ for the given reaction is -238.7 kJ

Explanation:

The given reaction can be written as summation of three elementary steps such as:

$C(graphite)+O_{2}(g)\rightarrow CO_{2}(g)$ $\Delta H_{1}= -393.5 kJ$

$2H_{2}(g)+O_{2}(g)\rightarrow 2H_{2}O(l)$ $\Delta H_{2}= (2\times -285.8)kJ$

$CO_{2}(g)+2H_{2}O(l)\rightarrow CH_{3}OH(l)+\frac{3}{2}O_{2}(g)$ $\Delta H_{3}= 726.4 kJ$

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$C(graphite)+2H_{2}(g)+\frac{1}{2}O_{2}(g)\rightarrow CH_{3}OH(l)$

$\Delta H=\Delta H_{1}+\Delta H_{2}+\Delta H_{3}=-238.7 kJ$

4 0

3 years ago

What is the molar mass of Al2(SO4)3

umka21 [38]

Answer:

The molar mass of $Al_2(SO_4)_3$ is 342.145 g/mol

Explanation:

The molar mass is stated as the “mass per unit amount of substance”of a given chemical compound

$Al_2(SO_4)_3$ is Aluminium sulphate. They easily dissolve in water. It is primarily used as a 'coagulating agent' in the drinking water purification and also in waste and sewage water treatment plants,

We know,

Atomic weight of Aluminium = 26.981

Atomic weight of Sulphur= 32.065

Atomic weight of Oxygen = 15.9994

Now molar mass of $Al_2(SO_4)_3$ (Aluminium sulphate) is

=>2(26.981)+3(32.065+4(15.999))

=>53.962 +3(32.065+63.996)

=>53.962+3(96.061)

=>53.962+288.183

=>342.145

4 0

3 years ago

Which solution will form a precipitate when mixed with a solution of aqueous na2co3? which solution will form a precipitate when

trapecia [35]

Answer:

$CuCl_{2}(aq.)$ will form a precipitate of insoluble $CuCO_{3}$ when aqueous $Na_{2}CO_{3}$ is added.

Explanation:

According to solubility rule-

all carbonates are insoluble except group IA compounds and $NH_{4}^{+}$

all salts of sodium are soluble

When $Na_{2}CO_{3}$ is added to given solutions, a double displacement reaction takes place in each solution to form a sodium salt and a carbonate salt.

So, in accordance with solubility rule, addition of $Na_{2}CO_{3}$ into $CuCl_{2}(aq.)$ will result precipitation of insoluble $CuCO_{3}$

Reaction: $Na_{2}CO_{3}(aq.)+CuCl_{2}(aq.)\rightarrow 2NaCl(aq.)+CuCO_{3}(aq.)$

4 0

3 years ago