<span>Find the wind speed and the plane's airspeed.
:
Let s = speed of the plane in still air
Let w = speed of the wind
then
(s-w) = plane speed against the wind
and
(s+w) = plane speed with the wind
:
Change 3 3/8 hrs to 3.375 hrs
:
The trips there and back are equal distance, (1890 mi) write two distance equations
dist = time * speed
:
3.375(s-w) = 1890
3.0(s + w) = 1890
:
It is convenient that we can simplify both these equations:
divide the 1st by 3.375
divide the 2nd by 3
resulting in two simple equations that can be used for elimination of w
s - w = 560
s + w = 630
----------------adding eliminates w, find s
2s = 1190
s =
s = 595 mph is the plane speed in still air
Find w
595 + w = 630
w = 630 - 595
w = 35 mph is the wind spee</span>
I am pretty sure that the answer is 4/5, hope this helped :)
H(x) equals what? I think you've missed that detail. :)
The perpendicular bisector theorem gives the statements that ensures
that 
and 
are perpendicular.
The two statements if true that guarantee is perpendicular to line are;
Reasons:
The given diagram is the construction of the line 
perpendicular to line 
.
Required:
The two statements that guarantee that is perpendicular to line .
Solution:
From the point <em>C</em> arcs <em>E</em> and <em>D</em> are drawn to cross line , therefore;
arcs drawn from the same radius.
is perpendicular to line , given.
Therefore;
by perpendicular bisector theorem.
Learn more about the perpendicular bisector theorem here:
brainly.com/question/11357763
